Plotting a Maclaurin series Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm...

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Plotting a Maclaurin series



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
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1












$begingroup$


Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.



Please help, I've tried everything I could think of.










share|improve this question









New contributor




nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$








  • 1




    $begingroup$
    Possible duplicates: (7559), (130464), (158080), (160684)
    $endgroup$
    – Michael E2
    3 hours ago
















1












$begingroup$


Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.



Please help, I've tried everything I could think of.










share|improve this question









New contributor




nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    Possible duplicates: (7559), (130464), (158080), (160684)
    $endgroup$
    – Michael E2
    3 hours ago














1












1








1





$begingroup$


Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.



Please help, I've tried everything I could think of.










share|improve this question









New contributor




nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Can anyone plot the degree-8 Maclaurin polynomial for the function $(x+1)/((x^2)-9)$ and function $(x+1)/((x^2)-9)$ on the same plot.



Please help, I've tried everything I could think of.







plotting series-expansion






share|improve this question









New contributor




nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 4 hours ago









m_goldberg

89k873200




89k873200






New contributor




nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 5 hours ago









niknik

61




61




New contributor




nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






nik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    $begingroup$
    Possible duplicates: (7559), (130464), (158080), (160684)
    $endgroup$
    – Michael E2
    3 hours ago














  • 1




    $begingroup$
    Possible duplicates: (7559), (130464), (158080), (160684)
    $endgroup$
    – Michael E2
    3 hours ago








1




1




$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
3 hours ago




$begingroup$
Possible duplicates: (7559), (130464), (158080), (160684)
$endgroup$
– Michael E2
3 hours ago










1 Answer
1






active

oldest

votes


















4












$begingroup$

The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.



f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]


enter image description here






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    Plotting over a wider range will highlight the differences. Plot[{f, p}, {x, -4, 4}, PlotRange -> {-3, 3}, PlotLegends -> Placed[{"function", "polynomial"}, {.7, .7}]]
    $endgroup$
    – Bob Hanlon
    1 hour ago












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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4












$begingroup$

The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.



f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]


enter image description here






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    Plotting over a wider range will highlight the differences. Plot[{f, p}, {x, -4, 4}, PlotRange -> {-3, 3}, PlotLegends -> Placed[{"function", "polynomial"}, {.7, .7}]]
    $endgroup$
    – Bob Hanlon
    1 hour ago
















4












$begingroup$

The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.



f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]


enter image description here






share|improve this answer









$endgroup$









  • 1




    $begingroup$
    Plotting over a wider range will highlight the differences. Plot[{f, p}, {x, -4, 4}, PlotRange -> {-3, 3}, PlotLegends -> Placed[{"function", "polynomial"}, {.7, .7}]]
    $endgroup$
    – Bob Hanlon
    1 hour ago














4












4








4





$begingroup$

The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.



f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]


enter image description here






share|improve this answer









$endgroup$



The problem is probably that Series returns a SeriesData object. It must be converted to a polynomial with Normal before it can be plotted.



f = (x + 1)/((x^2) - 9);
p = Normal[Series[f, {x, 0, 8}]]
Plot[{f, p}, {x, -2, 2}]


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered 4 hours ago









Henrik SchumacherHenrik Schumacher

60.8k585171




60.8k585171








  • 1




    $begingroup$
    Plotting over a wider range will highlight the differences. Plot[{f, p}, {x, -4, 4}, PlotRange -> {-3, 3}, PlotLegends -> Placed[{"function", "polynomial"}, {.7, .7}]]
    $endgroup$
    – Bob Hanlon
    1 hour ago














  • 1




    $begingroup$
    Plotting over a wider range will highlight the differences. Plot[{f, p}, {x, -4, 4}, PlotRange -> {-3, 3}, PlotLegends -> Placed[{"function", "polynomial"}, {.7, .7}]]
    $endgroup$
    – Bob Hanlon
    1 hour ago








1




1




$begingroup$
Plotting over a wider range will highlight the differences. Plot[{f, p}, {x, -4, 4}, PlotRange -> {-3, 3}, PlotLegends -> Placed[{"function", "polynomial"}, {.7, .7}]]
$endgroup$
– Bob Hanlon
1 hour ago




$begingroup$
Plotting over a wider range will highlight the differences. Plot[{f, p}, {x, -4, 4}, PlotRange -> {-3, 3}, PlotLegends -> Placed[{"function", "polynomial"}, {.7, .7}]]
$endgroup$
– Bob Hanlon
1 hour ago










nik is a new contributor. Be nice, and check out our Code of Conduct.










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