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OpenLayers freehanddraw forEachFeatureInExtent returns features not in shape
How to detect touch events on mobile browsers with OpenLayers 3?Buffering multiple features with Geoserver WPSOpenLayers 3: getting rid of 'blue dot' selection iconRendering freehand drawn geometry from geojson on map with OpenLayers?How to merge two (or more) features in OpenLayers?OL 4.2 WMS getGetFeatureInfoUrl producing incorrect URLUse map.on Click for different events (edit Drawing, Popup) on Openlayers maplayer get extent returns null openlayers 4OpenLayers 4 getGetFeatureInfoUrl and HitTolleranceopenlayers 3 ol.source.ImageWMS.getGetFeatureInfoUrl returns bad XY
I am not a newbie.
I am trying to get the features(icons) found inside a closed freehand line.
The approach I am taking is to take the extent returned from the drawing and
use it to get the features(icons) inside the drawing. This works. It includes some extra features(icons). Is there a better approach to finding featues(icons) inside the freehand drawing that is more accurate? If not I have had some success using the following:
The extent returned with draw.on('drawend', function (event) {
is used to get features in closed line drawn on map.
vectorSource.forEachFeatureInExtent will have features not inside drawing
var geomA = event.feature.getGeometry();
var bhpoints = geomA.flatCoordinates;
I use these flatCoordinates(xy) to compare to each feature to get a more
accurate decision whether the feature is in or outside of the closed line.
This works but will miss once and a while.
To restate my goal:
I want to find the features(icons) inside of a freehand drawing and the
obvious solution with extents needs better accuracy.
openlayers
edited Feb 9 at 18:15
Vince
14.7k32749
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
bumped to the homepage by Community♦ 27 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I am not a newbie.
I am trying to get the features(icons) found inside a closed freehand line.
The approach I am taking is to take the extent returned from the drawing and
use it to get the features(icons) inside the drawing. This works. It includes some extra features(icons). Is there a better approach to finding featues(icons) inside the freehand drawing that is more accurate? If not I have had some success using the following:
The extent returned with draw.on('drawend', function (event) {
is used to get features in closed line drawn on map.
vectorSource.forEachFeatureInExtent will have features not inside drawing
var geomA = event.feature.getGeometry();
var bhpoints = geomA.flatCoordinates;
I use these flatCoordinates(xy) to compare to each feature to get a more
accurate decision whether the feature is in or outside of the closed line.
This works but will miss once and a while.
To restate my goal:
I want to find the features(icons) inside of a freehand drawing and the
obvious solution with extents needs better accuracy.
openlayers
edited Feb 9 at 18:15
Vince
14.7k32749
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
bumped to the homepage by Community♦ 27 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I am not a newbie.
I am trying to get the features(icons) found inside a closed freehand line.
The approach I am taking is to take the extent returned from the drawing and
use it to get the features(icons) inside the drawing. This works. It includes some extra features(icons). Is there a better approach to finding featues(icons) inside the freehand drawing that is more accurate? If not I have had some success using the following:
The extent returned with draw.on('drawend', function (event) {
is used to get features in closed line drawn on map.
vectorSource.forEachFeatureInExtent will have features not inside drawing
var geomA = event.feature.getGeometry();
var bhpoints = geomA.flatCoordinates;
I use these flatCoordinates(xy) to compare to each feature to get a more
accurate decision whether the feature is in or outside of the closed line.
This works but will miss once and a while.
To restate my goal:
I want to find the features(icons) inside of a freehand drawing and the
obvious solution with extents needs better accuracy.
openlayers
edited Feb 9 at 18:15
Vince
14.7k32749
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
I am not a newbie.
I am trying to get the features(icons) found inside a closed freehand line.
The approach I am taking is to take the extent returned from the drawing and
use it to get the features(icons) inside the drawing. This works. It includes some extra features(icons). Is there a better approach to finding featues(icons) inside the freehand drawing that is more accurate? If not I have had some success using the following:
The extent returned with draw.on('drawend', function (event) {
is used to get features in closed line drawn on map.
vectorSource.forEachFeatureInExtent will have features not inside drawing
var geomA = event.feature.getGeometry();
var bhpoints = geomA.flatCoordinates;
I use these flatCoordinates(xy) to compare to each feature to get a more
accurate decision whether the feature is in or outside of the closed line.
This works but will miss once and a while.
To restate my goal:
I want to find the features(icons) inside of a freehand drawing and the
obvious solution with extents needs better accuracy.
openlayers
openlayers
edited Feb 9 at 18:15
Vince
14.7k32749
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
edited Feb 9 at 18:15
Vince
14.7k32749
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
edited Feb 9 at 18:15
Vince
14.7k32749
edited Feb 9 at 18:15
Vince
14.7k32749
edited Feb 9 at 18:15
Vince
14.7k32749
14.7k32749
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
asked Feb 9 at 17:54
William HuntWilliam Hunt
62
62
bumped to the homepage by Community♦ 27 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 27 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
If by 'closed freehand line' you mean freehand polygon you could check each point feature in the extent is inside the polygon geometry:
vectorSource.forEachFeatureInExtent(geomA.getExtent(), function(feature) {
if (feature.getGeometry().getType() == 'Point' && geomA.intersectsCoordinate(feature.getGeometry().getCoordinates()) {
....
....
}
});
answered Feb 9 at 21:22
MikeMike
2,215139
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
If by 'closed freehand line' you mean freehand polygon you could check each point feature in the extent is inside the polygon geometry:
vectorSource.forEachFeatureInExtent(geomA.getExtent(), function(feature) {
if (feature.getGeometry().getType() == 'Point' && geomA.intersectsCoordinate(feature.getGeometry().getCoordinates()) {
....
....
}
});
answered Feb 9 at 21:22
MikeMike
2,215139
add a comment |
If by 'closed freehand line' you mean freehand polygon you could check each point feature in the extent is inside the polygon geometry:
vectorSource.forEachFeatureInExtent(geomA.getExtent(), function(feature) {
if (feature.getGeometry().getType() == 'Point' && geomA.intersectsCoordinate(feature.getGeometry().getCoordinates()) {
....
....
}
});
answered Feb 9 at 21:22
MikeMike
2,215139
add a comment |
If by 'closed freehand line' you mean freehand polygon you could check each point feature in the extent is inside the polygon geometry:
vectorSource.forEachFeatureInExtent(geomA.getExtent(), function(feature) {
if (feature.getGeometry().getType() == 'Point' && geomA.intersectsCoordinate(feature.getGeometry().getCoordinates()) {
....
....
}
});
answered Feb 9 at 21:22
MikeMike
2,215139
If by 'closed freehand line' you mean freehand polygon you could check each point feature in the extent is inside the polygon geometry:
vectorSource.forEachFeatureInExtent(geomA.getExtent(), function(feature) {
if (feature.getGeometry().getType() == 'Point' && geomA.intersectsCoordinate(feature.getGeometry().getCoordinates()) {
....
....
}
});
answered Feb 9 at 21:22
MikeMike
2,215139
answered Feb 9 at 21:22
MikeMike
2,215139
answered Feb 9 at 21:22
MikeMike
2,215139
answered Feb 9 at 21:22
MikeMike
2,215139
2,215139
add a comment |
add a comment |
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