How can I request WFS data using GeoServer's viewparams with pyqgis?Obtaining feature using ArcGIS for Server...
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How can I request WFS data using GeoServer's viewparams with pyqgis?
Obtaining feature using ArcGIS for Server and WFS based on featureid?QGIS 2.16 adding certain WFS failedMapServer propertyname=fieldname only works when using gml as outputError connecting to gov.uk WFS in QGIS 2.18.15WFS: DescribeFeatureType query with typenames?issue with TYPENAME(s) in KVP for WFSBBox and KVP for WFSproblem with Bounding Box GetFeature WFSGetFeature request issue with WFSDownloading WFS data using QGIS?
Using pyqgis how can I request WFS data using GeoServer's viewparams request parameter?
I can use the viewparams request parameter to obtain the filtered WFS data I require via my web browser but not via pyqgis.
The below returns the results I require via a browser and this appears to be valid WFS GML
(Where <LDS_API_KEY>
is the auth key generated by registered users via https://data.linz.govt.nz/. Please let me know if you can help and don't want to register and perhaps I can generate a temporary key to share)
https://data.linz.govt.nz/services;key=<LDS_API_KEY>/wfs?
SERVICE=wfs&VERSION=2.0.0&
REQUEST=GetFeature&
TYPENAMES=data.linz.govt.nz:layer-53353-changeset&
viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z
via pyqgis when trying to create a WFS vector layer with the same URL with the viewparams I get a invalid layer:
url = 'https://data.linz.govt.nz/services;key=<LINZ_API_KEY>/wfs?SERVICE=wfs&VERSION=2.0.0&REQUEST=GetFeature&TYPENAME=data.linz.govt.nz:layer-53353-changeset&viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z'
layer = QgsVectorLayer(url, 'test', 'WFS')
layer.isValid()
>>> False
How can I request my WFS data with a viewparams filter?
qgis pyqgis wfs pyqgis-3
New contributor
add a comment |
Using pyqgis how can I request WFS data using GeoServer's viewparams request parameter?
I can use the viewparams request parameter to obtain the filtered WFS data I require via my web browser but not via pyqgis.
The below returns the results I require via a browser and this appears to be valid WFS GML
(Where <LDS_API_KEY>
is the auth key generated by registered users via https://data.linz.govt.nz/. Please let me know if you can help and don't want to register and perhaps I can generate a temporary key to share)
https://data.linz.govt.nz/services;key=<LDS_API_KEY>/wfs?
SERVICE=wfs&VERSION=2.0.0&
REQUEST=GetFeature&
TYPENAMES=data.linz.govt.nz:layer-53353-changeset&
viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z
via pyqgis when trying to create a WFS vector layer with the same URL with the viewparams I get a invalid layer:
url = 'https://data.linz.govt.nz/services;key=<LINZ_API_KEY>/wfs?SERVICE=wfs&VERSION=2.0.0&REQUEST=GetFeature&TYPENAME=data.linz.govt.nz:layer-53353-changeset&viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z'
layer = QgsVectorLayer(url, 'test', 'WFS')
layer.isValid()
>>> False
How can I request my WFS data with a viewparams filter?
qgis pyqgis wfs pyqgis-3
New contributor
add a comment |
Using pyqgis how can I request WFS data using GeoServer's viewparams request parameter?
I can use the viewparams request parameter to obtain the filtered WFS data I require via my web browser but not via pyqgis.
The below returns the results I require via a browser and this appears to be valid WFS GML
(Where <LDS_API_KEY>
is the auth key generated by registered users via https://data.linz.govt.nz/. Please let me know if you can help and don't want to register and perhaps I can generate a temporary key to share)
https://data.linz.govt.nz/services;key=<LDS_API_KEY>/wfs?
SERVICE=wfs&VERSION=2.0.0&
REQUEST=GetFeature&
TYPENAMES=data.linz.govt.nz:layer-53353-changeset&
viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z
via pyqgis when trying to create a WFS vector layer with the same URL with the viewparams I get a invalid layer:
url = 'https://data.linz.govt.nz/services;key=<LINZ_API_KEY>/wfs?SERVICE=wfs&VERSION=2.0.0&REQUEST=GetFeature&TYPENAME=data.linz.govt.nz:layer-53353-changeset&viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z'
layer = QgsVectorLayer(url, 'test', 'WFS')
layer.isValid()
>>> False
How can I request my WFS data with a viewparams filter?
qgis pyqgis wfs pyqgis-3
New contributor
Using pyqgis how can I request WFS data using GeoServer's viewparams request parameter?
I can use the viewparams request parameter to obtain the filtered WFS data I require via my web browser but not via pyqgis.
The below returns the results I require via a browser and this appears to be valid WFS GML
(Where <LDS_API_KEY>
is the auth key generated by registered users via https://data.linz.govt.nz/. Please let me know if you can help and don't want to register and perhaps I can generate a temporary key to share)
https://data.linz.govt.nz/services;key=<LDS_API_KEY>/wfs?
SERVICE=wfs&VERSION=2.0.0&
REQUEST=GetFeature&
TYPENAMES=data.linz.govt.nz:layer-53353-changeset&
viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z
via pyqgis when trying to create a WFS vector layer with the same URL with the viewparams I get a invalid layer:
url = 'https://data.linz.govt.nz/services;key=<LINZ_API_KEY>/wfs?SERVICE=wfs&VERSION=2.0.0&REQUEST=GetFeature&TYPENAME=data.linz.govt.nz:layer-53353-changeset&viewparams=from:2018-12-23T01:41:20.703998Z;to:2018-12-30T01:46:55.913620Z'
layer = QgsVectorLayer(url, 'test', 'WFS')
layer.isValid()
>>> False
How can I request my WFS data with a viewparams filter?
qgis pyqgis wfs pyqgis-3
qgis pyqgis wfs pyqgis-3
New contributor
New contributor
edited 3 mins ago
Vince
14.8k32849
14.8k32849
New contributor
asked 11 mins ago
HuntMasterHuntMaster
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