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Overlay a spatial polygon with a grid and check in which grid element specific coordinates are located


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}







30















How can one use R to





  1. split a shapefile in 200 meter squares/sub-polygons,


  2. plot this grid (incl. ID numbers for each square) over the original map below, and

  3. evaluate in which square specific geographic coordinates are located.


I am a beginner in GIS and this is perhaps a basic question, but I haven't found a tutorial on how to do this in R.



What I have done so far is loading a shapefile of NYC and plotting some exemplary geographic coordinates.



I appreciate any general advice, but I am looking for an example (R code) how to this with the data below.



# Load packages 
library(maptools)

# Download shapefile for NYC
# OLD URL (no longer working)
# shpurl <- "http://www.nyc.gov/html/dcp/download/bytes/nybb_13a.zip"
shpurl <- "https://www1.nyc.gov/assets/planning/download/zip/data-maps/open-data/nybb_13a.zip"

tmp <- tempfile(fileext=".zip")
download.file(shpurl, destfile=tmp)
files <- unzip(tmp, exdir=getwd())

# Load & plot shapefile
shp <- readShapePoly(files[grep(".shp$", files)])
plot(shp)

# Define coordinates
points_of_interest <- data.frame(y=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
x =c(130600, 150600, 180600, 198000, 248000, 218000),
id =c("A"), stringsAsFactors=F)

# Plot coordinates
points(points_of_interest$y, points_of_interest$x, pch=19, col="red")


enter image description here










share|improve this question

























  • See also stackoverflow.com/q/17801398/287948

    – Peter Krauss
    Mar 22 '14 at 7:51


















30















How can one use R to





  1. split a shapefile in 200 meter squares/sub-polygons,


  2. plot this grid (incl. ID numbers for each square) over the original map below, and

  3. evaluate in which square specific geographic coordinates are located.


I am a beginner in GIS and this is perhaps a basic question, but I haven't found a tutorial on how to do this in R.



What I have done so far is loading a shapefile of NYC and plotting some exemplary geographic coordinates.



I appreciate any general advice, but I am looking for an example (R code) how to this with the data below.



# Load packages 
library(maptools)

# Download shapefile for NYC
# OLD URL (no longer working)
# shpurl <- "http://www.nyc.gov/html/dcp/download/bytes/nybb_13a.zip"
shpurl <- "https://www1.nyc.gov/assets/planning/download/zip/data-maps/open-data/nybb_13a.zip"

tmp <- tempfile(fileext=".zip")
download.file(shpurl, destfile=tmp)
files <- unzip(tmp, exdir=getwd())

# Load & plot shapefile
shp <- readShapePoly(files[grep(".shp$", files)])
plot(shp)

# Define coordinates
points_of_interest <- data.frame(y=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
x =c(130600, 150600, 180600, 198000, 248000, 218000),
id =c("A"), stringsAsFactors=F)

# Plot coordinates
points(points_of_interest$y, points_of_interest$x, pch=19, col="red")


enter image description here










share|improve this question

























  • See also stackoverflow.com/q/17801398/287948

    – Peter Krauss
    Mar 22 '14 at 7:51














30












30








30


21






How can one use R to





  1. split a shapefile in 200 meter squares/sub-polygons,


  2. plot this grid (incl. ID numbers for each square) over the original map below, and

  3. evaluate in which square specific geographic coordinates are located.


I am a beginner in GIS and this is perhaps a basic question, but I haven't found a tutorial on how to do this in R.



What I have done so far is loading a shapefile of NYC and plotting some exemplary geographic coordinates.



I appreciate any general advice, but I am looking for an example (R code) how to this with the data below.



# Load packages 
library(maptools)

# Download shapefile for NYC
# OLD URL (no longer working)
# shpurl <- "http://www.nyc.gov/html/dcp/download/bytes/nybb_13a.zip"
shpurl <- "https://www1.nyc.gov/assets/planning/download/zip/data-maps/open-data/nybb_13a.zip"

tmp <- tempfile(fileext=".zip")
download.file(shpurl, destfile=tmp)
files <- unzip(tmp, exdir=getwd())

# Load & plot shapefile
shp <- readShapePoly(files[grep(".shp$", files)])
plot(shp)

# Define coordinates
points_of_interest <- data.frame(y=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
x =c(130600, 150600, 180600, 198000, 248000, 218000),
id =c("A"), stringsAsFactors=F)

# Plot coordinates
points(points_of_interest$y, points_of_interest$x, pch=19, col="red")


enter image description here










share|improve this question
















How can one use R to





  1. split a shapefile in 200 meter squares/sub-polygons,


  2. plot this grid (incl. ID numbers for each square) over the original map below, and

  3. evaluate in which square specific geographic coordinates are located.


I am a beginner in GIS and this is perhaps a basic question, but I haven't found a tutorial on how to do this in R.



What I have done so far is loading a shapefile of NYC and plotting some exemplary geographic coordinates.



I appreciate any general advice, but I am looking for an example (R code) how to this with the data below.



# Load packages 
library(maptools)

# Download shapefile for NYC
# OLD URL (no longer working)
# shpurl <- "http://www.nyc.gov/html/dcp/download/bytes/nybb_13a.zip"
shpurl <- "https://www1.nyc.gov/assets/planning/download/zip/data-maps/open-data/nybb_13a.zip"

tmp <- tempfile(fileext=".zip")
download.file(shpurl, destfile=tmp)
files <- unzip(tmp, exdir=getwd())

# Load & plot shapefile
shp <- readShapePoly(files[grep(".shp$", files)])
plot(shp)

# Define coordinates
points_of_interest <- data.frame(y=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
x =c(130600, 150600, 180600, 198000, 248000, 218000),
id =c("A"), stringsAsFactors=F)

# Plot coordinates
points(points_of_interest$y, points_of_interest$x, pch=19, col="red")


enter image description here







r vector-grid point-in-polygon






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Apr 14 '18 at 20:07









nmtoken

8,08642866




8,08642866










asked Mar 6 '14 at 22:02









majommajom

156129




156129













  • See also stackoverflow.com/q/17801398/287948

    – Peter Krauss
    Mar 22 '14 at 7:51



















  • See also stackoverflow.com/q/17801398/287948

    – Peter Krauss
    Mar 22 '14 at 7:51

















See also stackoverflow.com/q/17801398/287948

– Peter Krauss
Mar 22 '14 at 7:51





See also stackoverflow.com/q/17801398/287948

– Peter Krauss
Mar 22 '14 at 7:51










5 Answers
5






active

oldest

votes


















34





+100









Here is an example using a SpatialGrid object:



### read shapefile
library("rgdal")
shp <- readOGR("nybb_13a", "nybb")

proj4string(shp) # units us-ft
# [1] "+proj=lcc +lat_1=40.66666666666666 +lat_2=41.03333333333333
# +lat_0=40.16666666666666 +lon_0=-74 +x_0=300000 +y_0=0 +datum=NAD83
# +units=us-ft +no_defs +ellps=GRS80 +towgs84=0,0,0"

### define coordinates and convert to SpatialPointsDataFrame
poi <- data.frame(x=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
y=c(130600, 150600, 180600, 198000, 248000, 218000),
id="A", stringsAsFactors=F)
coordinates(poi) <- ~ x + y
proj4string(poi) <- proj4string(shp)

### define SpatialGrid object
bb <- bbox(shp)
cs <- c(3.28084, 3.28084)*6000 # cell size 6km x 6km (for illustration)
# 1 ft = 3.28084 m
cc <- bb[, 1] + (cs/2) # cell offset
cd <- ceiling(diff(t(bb))/cs) # number of cells per direction
grd <- GridTopology(cellcentre.offset=cc, cellsize=cs, cells.dim=cd)
grd
# cellcentre.offset 923018 129964
# cellsize 19685 19685
# cells.dim 8 8

sp_grd <- SpatialGridDataFrame(grd,
data=data.frame(id=1:prod(cd)),
proj4string=CRS(proj4string(shp)))
summary(sp_grd)
# Object of class SpatialGridDataFrame
# Coordinates:
# min max
# x 913175 1070655
# y 120122 277602
# Is projected: TRUE
# ...


Now you can use the implemented over-method to obtain the cell IDs:



over(poi, sp_grd)
# id
# 1 57
# 2 51
# 3 38
# 4 39
# 5 14
# 6 28


To plot the shapefile and the grid with the cell IDs:



library("lattice")
spplot(sp_grd, "id",
panel = function(...) {
panel.gridplot(..., border="black")
sp.polygons(shp)
sp.points(poi, cex=1.5)
panel.text(...)
})


spplot1



or without colour/colour key:



library("lattice")
spplot(sp_grd, "id", colorkey=FALSE,
panel = function(...) {
panel.gridplot(..., border="black", col.regions="white")
sp.polygons(shp)
sp.points(poi, cex=1.5)
panel.text(..., col="red")
})


spplot2






share|improve this answer


























  • This looks like an answer to me, but in case you are looking for something different. Try the r tag in stackoverflow stackoverflow.com/search?q=R+tag

    – Brad Nesom
    Mar 14 '14 at 2:26











  • @rcs this code looks just like what I am trying to do but my shapefile is in a different projection: proj4string (DK_reg1) [1] "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0" does anyone have any suggestions on how to break this shapefiles of this projection to 1000 equal sized grid cells? and then randomly select 100 of them and highlight them?

    – I Del Toro
    Sep 13 '14 at 11:34



















6














The New York dataset provided in the question is no longer available for download. I use the nc dataset from sf package to demonstrate a solution using sf package:



library(sf)
library(ggplot2)

# read nc polygon data and transform to UTM
nc <- st_read(system.file('shape/nc.shp', package = 'sf')) %>%
st_transform(32617)

# random sample of 5 points
pts <- st_sample(nc, size = 5) %>% st_sf

# create 50km grid - here you can substitute 200 for 50000
grid_50 <- st_make_grid(nc, cellsize = c(50000, 50000)) %>%
st_sf(grid_id = 1:length(.))

# create labels for each grid_id
grid_lab <- st_centroid(grid_50) %>% cbind(st_coordinates(.))

# view the sampled points, polygons and grid
ggplot() +
geom_sf(data = nc, fill = 'white', lwd = 0.05) +
geom_sf(data = pts, color = 'red', size = 1.7) +
geom_sf(data = grid_50, fill = 'transparent', lwd = 0.3) +
geom_text(data = grid_lab, aes(x = X, y = Y, label = grid_id), size = 2) +
coord_sf(datum = NA) +
labs(x = "") +
labs(y = "")

# which grid square is each point in?
pts %>% st_join(grid_50, join = st_intersects) %>% as.data.frame

#> grid_id geometry
#> 1 55 POINT (359040.7 3925435)
#> 2 96 POINT (717024 4007464)
#> 3 91 POINT (478906.6 4037308)
#> 4 40 POINT (449671.6 3901418)
#> 5 30 POINT (808971.4 3830231)


enter image description here






share|improve this answer
























  • Thanks. I updated the link in my question to relfect the changes on their webpage. Now it should work again.

    – majom
    Mar 5 '18 at 15:18











  • I really need to start using the sf package. This is awesome!

    – spacedSparking
    Mar 23 '18 at 20:41











  • Is there an easy way to only plot the grid cells that intersect with the state polygon?

    – spacedSparking
    Mar 23 '18 at 22:09











  • st_intersection(grid_50, nc) should do it

    – sebdalgarno
    Mar 24 '18 at 23:18



















2














Have you looked at the R raster package? It has tools to convert to/from vector GIS objects so you should be able to a) create a raster (grid) with 200x200m cells and b) convert it to a set of polygons with a logical id of some kind. From there I would look at the sp package to help with intersecting the points and the polygon grid. This http://cran.r-project.org/web/packages/sp/vignettes/over.pdf page might be a good start. Wandering through the sp package docs you might be able to start with the SpatialGrid-class and just skip the raster part entirely.






share|improve this answer



















  • 1





    Thanks for your comment. I already looked at those packages, but failed to implement this. This was why I was asking for an example.

    – majom
    Mar 10 '14 at 9:05



















0














The "GIS universe" is complex and have many standards that your data must be compliant. All "GIS tools" interoperates by GIS-standards. All "serious GIS data" today (2014) are stored in a database.



The best way to "use R" in a GIS context, with other FOSS tools, is embedded into SQL. The best tools are PostgreSQL 9.X (see PL/R) and PostGIS.





You answer:




  • To import/export shape files: use shp2pgsql and pgsql2shp.

  • To "split a shape file in 200 meter squares/sub-polygons": see ST_SnapToGrid(), ST_AsRaster(), etc. We need understand better your needs to express into a "recipe".

  • you say that need "geographic coordinates are located" .. perhaps ST_Centroid() of the squares (?)... You can express "more mathematically" so I understand.


... Perhaps you not need any raster convertion, only a matrix of regurlar-sampled points.





A primitive way is use R without PL/R, in a your usual external compiler: only convert your polygons and export as shape or as WKT (see ST_AsText), then convert data with awk or another filter to the R format.






share|improve this answer





















  • 1





    Thanks for your help. However, I would strongly prefer a solution which relies completely on R and existing packages. When I am able to split the shape file in 200m*200m subpolygons I can check with point.in.polygon which coordinates are in which polygons. My problem is to split the original shapefile in those sub-polygons.

    – majom
    Mar 9 '14 at 21:38













  • It is not a "SIG problem", try to ask at Stackoverflow directly.

    – Peter Krauss
    Mar 10 '14 at 11:18











  • See also how to deal with points of type SpatialPointsDataFrame, and a grid that is a raster at Stackoverflow.

    – Peter Krauss
    Mar 22 '14 at 7:54



















0














Is there way to dropping empty grids? or just griding the boundary of interest?






share|improve this answer








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    5 Answers
    5






    active

    oldest

    votes








    5 Answers
    5






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    34





    +100









    Here is an example using a SpatialGrid object:



    ### read shapefile
    library("rgdal")
    shp <- readOGR("nybb_13a", "nybb")

    proj4string(shp) # units us-ft
    # [1] "+proj=lcc +lat_1=40.66666666666666 +lat_2=41.03333333333333
    # +lat_0=40.16666666666666 +lon_0=-74 +x_0=300000 +y_0=0 +datum=NAD83
    # +units=us-ft +no_defs +ellps=GRS80 +towgs84=0,0,0"

    ### define coordinates and convert to SpatialPointsDataFrame
    poi <- data.frame(x=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
    y=c(130600, 150600, 180600, 198000, 248000, 218000),
    id="A", stringsAsFactors=F)
    coordinates(poi) <- ~ x + y
    proj4string(poi) <- proj4string(shp)

    ### define SpatialGrid object
    bb <- bbox(shp)
    cs <- c(3.28084, 3.28084)*6000 # cell size 6km x 6km (for illustration)
    # 1 ft = 3.28084 m
    cc <- bb[, 1] + (cs/2) # cell offset
    cd <- ceiling(diff(t(bb))/cs) # number of cells per direction
    grd <- GridTopology(cellcentre.offset=cc, cellsize=cs, cells.dim=cd)
    grd
    # cellcentre.offset 923018 129964
    # cellsize 19685 19685
    # cells.dim 8 8

    sp_grd <- SpatialGridDataFrame(grd,
    data=data.frame(id=1:prod(cd)),
    proj4string=CRS(proj4string(shp)))
    summary(sp_grd)
    # Object of class SpatialGridDataFrame
    # Coordinates:
    # min max
    # x 913175 1070655
    # y 120122 277602
    # Is projected: TRUE
    # ...


    Now you can use the implemented over-method to obtain the cell IDs:



    over(poi, sp_grd)
    # id
    # 1 57
    # 2 51
    # 3 38
    # 4 39
    # 5 14
    # 6 28


    To plot the shapefile and the grid with the cell IDs:



    library("lattice")
    spplot(sp_grd, "id",
    panel = function(...) {
    panel.gridplot(..., border="black")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(...)
    })


    spplot1



    or without colour/colour key:



    library("lattice")
    spplot(sp_grd, "id", colorkey=FALSE,
    panel = function(...) {
    panel.gridplot(..., border="black", col.regions="white")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(..., col="red")
    })


    spplot2






    share|improve this answer


























    • This looks like an answer to me, but in case you are looking for something different. Try the r tag in stackoverflow stackoverflow.com/search?q=R+tag

      – Brad Nesom
      Mar 14 '14 at 2:26











    • @rcs this code looks just like what I am trying to do but my shapefile is in a different projection: proj4string (DK_reg1) [1] "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0" does anyone have any suggestions on how to break this shapefiles of this projection to 1000 equal sized grid cells? and then randomly select 100 of them and highlight them?

      – I Del Toro
      Sep 13 '14 at 11:34
















    34





    +100









    Here is an example using a SpatialGrid object:



    ### read shapefile
    library("rgdal")
    shp <- readOGR("nybb_13a", "nybb")

    proj4string(shp) # units us-ft
    # [1] "+proj=lcc +lat_1=40.66666666666666 +lat_2=41.03333333333333
    # +lat_0=40.16666666666666 +lon_0=-74 +x_0=300000 +y_0=0 +datum=NAD83
    # +units=us-ft +no_defs +ellps=GRS80 +towgs84=0,0,0"

    ### define coordinates and convert to SpatialPointsDataFrame
    poi <- data.frame(x=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
    y=c(130600, 150600, 180600, 198000, 248000, 218000),
    id="A", stringsAsFactors=F)
    coordinates(poi) <- ~ x + y
    proj4string(poi) <- proj4string(shp)

    ### define SpatialGrid object
    bb <- bbox(shp)
    cs <- c(3.28084, 3.28084)*6000 # cell size 6km x 6km (for illustration)
    # 1 ft = 3.28084 m
    cc <- bb[, 1] + (cs/2) # cell offset
    cd <- ceiling(diff(t(bb))/cs) # number of cells per direction
    grd <- GridTopology(cellcentre.offset=cc, cellsize=cs, cells.dim=cd)
    grd
    # cellcentre.offset 923018 129964
    # cellsize 19685 19685
    # cells.dim 8 8

    sp_grd <- SpatialGridDataFrame(grd,
    data=data.frame(id=1:prod(cd)),
    proj4string=CRS(proj4string(shp)))
    summary(sp_grd)
    # Object of class SpatialGridDataFrame
    # Coordinates:
    # min max
    # x 913175 1070655
    # y 120122 277602
    # Is projected: TRUE
    # ...


    Now you can use the implemented over-method to obtain the cell IDs:



    over(poi, sp_grd)
    # id
    # 1 57
    # 2 51
    # 3 38
    # 4 39
    # 5 14
    # 6 28


    To plot the shapefile and the grid with the cell IDs:



    library("lattice")
    spplot(sp_grd, "id",
    panel = function(...) {
    panel.gridplot(..., border="black")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(...)
    })


    spplot1



    or without colour/colour key:



    library("lattice")
    spplot(sp_grd, "id", colorkey=FALSE,
    panel = function(...) {
    panel.gridplot(..., border="black", col.regions="white")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(..., col="red")
    })


    spplot2






    share|improve this answer


























    • This looks like an answer to me, but in case you are looking for something different. Try the r tag in stackoverflow stackoverflow.com/search?q=R+tag

      – Brad Nesom
      Mar 14 '14 at 2:26











    • @rcs this code looks just like what I am trying to do but my shapefile is in a different projection: proj4string (DK_reg1) [1] "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0" does anyone have any suggestions on how to break this shapefiles of this projection to 1000 equal sized grid cells? and then randomly select 100 of them and highlight them?

      – I Del Toro
      Sep 13 '14 at 11:34














    34





    +100







    34





    +100



    34




    +100





    Here is an example using a SpatialGrid object:



    ### read shapefile
    library("rgdal")
    shp <- readOGR("nybb_13a", "nybb")

    proj4string(shp) # units us-ft
    # [1] "+proj=lcc +lat_1=40.66666666666666 +lat_2=41.03333333333333
    # +lat_0=40.16666666666666 +lon_0=-74 +x_0=300000 +y_0=0 +datum=NAD83
    # +units=us-ft +no_defs +ellps=GRS80 +towgs84=0,0,0"

    ### define coordinates and convert to SpatialPointsDataFrame
    poi <- data.frame(x=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
    y=c(130600, 150600, 180600, 198000, 248000, 218000),
    id="A", stringsAsFactors=F)
    coordinates(poi) <- ~ x + y
    proj4string(poi) <- proj4string(shp)

    ### define SpatialGrid object
    bb <- bbox(shp)
    cs <- c(3.28084, 3.28084)*6000 # cell size 6km x 6km (for illustration)
    # 1 ft = 3.28084 m
    cc <- bb[, 1] + (cs/2) # cell offset
    cd <- ceiling(diff(t(bb))/cs) # number of cells per direction
    grd <- GridTopology(cellcentre.offset=cc, cellsize=cs, cells.dim=cd)
    grd
    # cellcentre.offset 923018 129964
    # cellsize 19685 19685
    # cells.dim 8 8

    sp_grd <- SpatialGridDataFrame(grd,
    data=data.frame(id=1:prod(cd)),
    proj4string=CRS(proj4string(shp)))
    summary(sp_grd)
    # Object of class SpatialGridDataFrame
    # Coordinates:
    # min max
    # x 913175 1070655
    # y 120122 277602
    # Is projected: TRUE
    # ...


    Now you can use the implemented over-method to obtain the cell IDs:



    over(poi, sp_grd)
    # id
    # 1 57
    # 2 51
    # 3 38
    # 4 39
    # 5 14
    # 6 28


    To plot the shapefile and the grid with the cell IDs:



    library("lattice")
    spplot(sp_grd, "id",
    panel = function(...) {
    panel.gridplot(..., border="black")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(...)
    })


    spplot1



    or without colour/colour key:



    library("lattice")
    spplot(sp_grd, "id", colorkey=FALSE,
    panel = function(...) {
    panel.gridplot(..., border="black", col.regions="white")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(..., col="red")
    })


    spplot2






    share|improve this answer















    Here is an example using a SpatialGrid object:



    ### read shapefile
    library("rgdal")
    shp <- readOGR("nybb_13a", "nybb")

    proj4string(shp) # units us-ft
    # [1] "+proj=lcc +lat_1=40.66666666666666 +lat_2=41.03333333333333
    # +lat_0=40.16666666666666 +lon_0=-74 +x_0=300000 +y_0=0 +datum=NAD83
    # +units=us-ft +no_defs +ellps=GRS80 +towgs84=0,0,0"

    ### define coordinates and convert to SpatialPointsDataFrame
    poi <- data.frame(x=c(919500, 959500, 1019500, 1049500, 1029500, 989500),
    y=c(130600, 150600, 180600, 198000, 248000, 218000),
    id="A", stringsAsFactors=F)
    coordinates(poi) <- ~ x + y
    proj4string(poi) <- proj4string(shp)

    ### define SpatialGrid object
    bb <- bbox(shp)
    cs <- c(3.28084, 3.28084)*6000 # cell size 6km x 6km (for illustration)
    # 1 ft = 3.28084 m
    cc <- bb[, 1] + (cs/2) # cell offset
    cd <- ceiling(diff(t(bb))/cs) # number of cells per direction
    grd <- GridTopology(cellcentre.offset=cc, cellsize=cs, cells.dim=cd)
    grd
    # cellcentre.offset 923018 129964
    # cellsize 19685 19685
    # cells.dim 8 8

    sp_grd <- SpatialGridDataFrame(grd,
    data=data.frame(id=1:prod(cd)),
    proj4string=CRS(proj4string(shp)))
    summary(sp_grd)
    # Object of class SpatialGridDataFrame
    # Coordinates:
    # min max
    # x 913175 1070655
    # y 120122 277602
    # Is projected: TRUE
    # ...


    Now you can use the implemented over-method to obtain the cell IDs:



    over(poi, sp_grd)
    # id
    # 1 57
    # 2 51
    # 3 38
    # 4 39
    # 5 14
    # 6 28


    To plot the shapefile and the grid with the cell IDs:



    library("lattice")
    spplot(sp_grd, "id",
    panel = function(...) {
    panel.gridplot(..., border="black")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(...)
    })


    spplot1



    or without colour/colour key:



    library("lattice")
    spplot(sp_grd, "id", colorkey=FALSE,
    panel = function(...) {
    panel.gridplot(..., border="black", col.regions="white")
    sp.polygons(shp)
    sp.points(poi, cex=1.5)
    panel.text(..., col="red")
    })


    spplot2







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Mar 12 '14 at 20:55

























    answered Mar 10 '14 at 21:53









    rcsrcs

    3,34911925




    3,34911925













    • This looks like an answer to me, but in case you are looking for something different. Try the r tag in stackoverflow stackoverflow.com/search?q=R+tag

      – Brad Nesom
      Mar 14 '14 at 2:26











    • @rcs this code looks just like what I am trying to do but my shapefile is in a different projection: proj4string (DK_reg1) [1] "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0" does anyone have any suggestions on how to break this shapefiles of this projection to 1000 equal sized grid cells? and then randomly select 100 of them and highlight them?

      – I Del Toro
      Sep 13 '14 at 11:34



















    • This looks like an answer to me, but in case you are looking for something different. Try the r tag in stackoverflow stackoverflow.com/search?q=R+tag

      – Brad Nesom
      Mar 14 '14 at 2:26











    • @rcs this code looks just like what I am trying to do but my shapefile is in a different projection: proj4string (DK_reg1) [1] "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0" does anyone have any suggestions on how to break this shapefiles of this projection to 1000 equal sized grid cells? and then randomly select 100 of them and highlight them?

      – I Del Toro
      Sep 13 '14 at 11:34

















    This looks like an answer to me, but in case you are looking for something different. Try the r tag in stackoverflow stackoverflow.com/search?q=R+tag

    – Brad Nesom
    Mar 14 '14 at 2:26





    This looks like an answer to me, but in case you are looking for something different. Try the r tag in stackoverflow stackoverflow.com/search?q=R+tag

    – Brad Nesom
    Mar 14 '14 at 2:26













    @rcs this code looks just like what I am trying to do but my shapefile is in a different projection: proj4string (DK_reg1) [1] "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0" does anyone have any suggestions on how to break this shapefiles of this projection to 1000 equal sized grid cells? and then randomly select 100 of them and highlight them?

    – I Del Toro
    Sep 13 '14 at 11:34





    @rcs this code looks just like what I am trying to do but my shapefile is in a different projection: proj4string (DK_reg1) [1] "+proj=longlat +datum=WGS84 +no_defs +ellps=WGS84 +towgs84=0,0,0" does anyone have any suggestions on how to break this shapefiles of this projection to 1000 equal sized grid cells? and then randomly select 100 of them and highlight them?

    – I Del Toro
    Sep 13 '14 at 11:34













    6














    The New York dataset provided in the question is no longer available for download. I use the nc dataset from sf package to demonstrate a solution using sf package:



    library(sf)
    library(ggplot2)

    # read nc polygon data and transform to UTM
    nc <- st_read(system.file('shape/nc.shp', package = 'sf')) %>%
    st_transform(32617)

    # random sample of 5 points
    pts <- st_sample(nc, size = 5) %>% st_sf

    # create 50km grid - here you can substitute 200 for 50000
    grid_50 <- st_make_grid(nc, cellsize = c(50000, 50000)) %>%
    st_sf(grid_id = 1:length(.))

    # create labels for each grid_id
    grid_lab <- st_centroid(grid_50) %>% cbind(st_coordinates(.))

    # view the sampled points, polygons and grid
    ggplot() +
    geom_sf(data = nc, fill = 'white', lwd = 0.05) +
    geom_sf(data = pts, color = 'red', size = 1.7) +
    geom_sf(data = grid_50, fill = 'transparent', lwd = 0.3) +
    geom_text(data = grid_lab, aes(x = X, y = Y, label = grid_id), size = 2) +
    coord_sf(datum = NA) +
    labs(x = "") +
    labs(y = "")

    # which grid square is each point in?
    pts %>% st_join(grid_50, join = st_intersects) %>% as.data.frame

    #> grid_id geometry
    #> 1 55 POINT (359040.7 3925435)
    #> 2 96 POINT (717024 4007464)
    #> 3 91 POINT (478906.6 4037308)
    #> 4 40 POINT (449671.6 3901418)
    #> 5 30 POINT (808971.4 3830231)


    enter image description here






    share|improve this answer
























    • Thanks. I updated the link in my question to relfect the changes on their webpage. Now it should work again.

      – majom
      Mar 5 '18 at 15:18











    • I really need to start using the sf package. This is awesome!

      – spacedSparking
      Mar 23 '18 at 20:41











    • Is there an easy way to only plot the grid cells that intersect with the state polygon?

      – spacedSparking
      Mar 23 '18 at 22:09











    • st_intersection(grid_50, nc) should do it

      – sebdalgarno
      Mar 24 '18 at 23:18
















    6














    The New York dataset provided in the question is no longer available for download. I use the nc dataset from sf package to demonstrate a solution using sf package:



    library(sf)
    library(ggplot2)

    # read nc polygon data and transform to UTM
    nc <- st_read(system.file('shape/nc.shp', package = 'sf')) %>%
    st_transform(32617)

    # random sample of 5 points
    pts <- st_sample(nc, size = 5) %>% st_sf

    # create 50km grid - here you can substitute 200 for 50000
    grid_50 <- st_make_grid(nc, cellsize = c(50000, 50000)) %>%
    st_sf(grid_id = 1:length(.))

    # create labels for each grid_id
    grid_lab <- st_centroid(grid_50) %>% cbind(st_coordinates(.))

    # view the sampled points, polygons and grid
    ggplot() +
    geom_sf(data = nc, fill = 'white', lwd = 0.05) +
    geom_sf(data = pts, color = 'red', size = 1.7) +
    geom_sf(data = grid_50, fill = 'transparent', lwd = 0.3) +
    geom_text(data = grid_lab, aes(x = X, y = Y, label = grid_id), size = 2) +
    coord_sf(datum = NA) +
    labs(x = "") +
    labs(y = "")

    # which grid square is each point in?
    pts %>% st_join(grid_50, join = st_intersects) %>% as.data.frame

    #> grid_id geometry
    #> 1 55 POINT (359040.7 3925435)
    #> 2 96 POINT (717024 4007464)
    #> 3 91 POINT (478906.6 4037308)
    #> 4 40 POINT (449671.6 3901418)
    #> 5 30 POINT (808971.4 3830231)


    enter image description here






    share|improve this answer
























    • Thanks. I updated the link in my question to relfect the changes on their webpage. Now it should work again.

      – majom
      Mar 5 '18 at 15:18











    • I really need to start using the sf package. This is awesome!

      – spacedSparking
      Mar 23 '18 at 20:41











    • Is there an easy way to only plot the grid cells that intersect with the state polygon?

      – spacedSparking
      Mar 23 '18 at 22:09











    • st_intersection(grid_50, nc) should do it

      – sebdalgarno
      Mar 24 '18 at 23:18














    6












    6








    6







    The New York dataset provided in the question is no longer available for download. I use the nc dataset from sf package to demonstrate a solution using sf package:



    library(sf)
    library(ggplot2)

    # read nc polygon data and transform to UTM
    nc <- st_read(system.file('shape/nc.shp', package = 'sf')) %>%
    st_transform(32617)

    # random sample of 5 points
    pts <- st_sample(nc, size = 5) %>% st_sf

    # create 50km grid - here you can substitute 200 for 50000
    grid_50 <- st_make_grid(nc, cellsize = c(50000, 50000)) %>%
    st_sf(grid_id = 1:length(.))

    # create labels for each grid_id
    grid_lab <- st_centroid(grid_50) %>% cbind(st_coordinates(.))

    # view the sampled points, polygons and grid
    ggplot() +
    geom_sf(data = nc, fill = 'white', lwd = 0.05) +
    geom_sf(data = pts, color = 'red', size = 1.7) +
    geom_sf(data = grid_50, fill = 'transparent', lwd = 0.3) +
    geom_text(data = grid_lab, aes(x = X, y = Y, label = grid_id), size = 2) +
    coord_sf(datum = NA) +
    labs(x = "") +
    labs(y = "")

    # which grid square is each point in?
    pts %>% st_join(grid_50, join = st_intersects) %>% as.data.frame

    #> grid_id geometry
    #> 1 55 POINT (359040.7 3925435)
    #> 2 96 POINT (717024 4007464)
    #> 3 91 POINT (478906.6 4037308)
    #> 4 40 POINT (449671.6 3901418)
    #> 5 30 POINT (808971.4 3830231)


    enter image description here






    share|improve this answer













    The New York dataset provided in the question is no longer available for download. I use the nc dataset from sf package to demonstrate a solution using sf package:



    library(sf)
    library(ggplot2)

    # read nc polygon data and transform to UTM
    nc <- st_read(system.file('shape/nc.shp', package = 'sf')) %>%
    st_transform(32617)

    # random sample of 5 points
    pts <- st_sample(nc, size = 5) %>% st_sf

    # create 50km grid - here you can substitute 200 for 50000
    grid_50 <- st_make_grid(nc, cellsize = c(50000, 50000)) %>%
    st_sf(grid_id = 1:length(.))

    # create labels for each grid_id
    grid_lab <- st_centroid(grid_50) %>% cbind(st_coordinates(.))

    # view the sampled points, polygons and grid
    ggplot() +
    geom_sf(data = nc, fill = 'white', lwd = 0.05) +
    geom_sf(data = pts, color = 'red', size = 1.7) +
    geom_sf(data = grid_50, fill = 'transparent', lwd = 0.3) +
    geom_text(data = grid_lab, aes(x = X, y = Y, label = grid_id), size = 2) +
    coord_sf(datum = NA) +
    labs(x = "") +
    labs(y = "")

    # which grid square is each point in?
    pts %>% st_join(grid_50, join = st_intersects) %>% as.data.frame

    #> grid_id geometry
    #> 1 55 POINT (359040.7 3925435)
    #> 2 96 POINT (717024 4007464)
    #> 3 91 POINT (478906.6 4037308)
    #> 4 40 POINT (449671.6 3901418)
    #> 5 30 POINT (808971.4 3830231)


    enter image description here







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 5 '18 at 1:47









    sebdalgarnosebdalgarno

    913410




    913410













    • Thanks. I updated the link in my question to relfect the changes on their webpage. Now it should work again.

      – majom
      Mar 5 '18 at 15:18











    • I really need to start using the sf package. This is awesome!

      – spacedSparking
      Mar 23 '18 at 20:41











    • Is there an easy way to only plot the grid cells that intersect with the state polygon?

      – spacedSparking
      Mar 23 '18 at 22:09











    • st_intersection(grid_50, nc) should do it

      – sebdalgarno
      Mar 24 '18 at 23:18



















    • Thanks. I updated the link in my question to relfect the changes on their webpage. Now it should work again.

      – majom
      Mar 5 '18 at 15:18











    • I really need to start using the sf package. This is awesome!

      – spacedSparking
      Mar 23 '18 at 20:41











    • Is there an easy way to only plot the grid cells that intersect with the state polygon?

      – spacedSparking
      Mar 23 '18 at 22:09











    • st_intersection(grid_50, nc) should do it

      – sebdalgarno
      Mar 24 '18 at 23:18

















    Thanks. I updated the link in my question to relfect the changes on their webpage. Now it should work again.

    – majom
    Mar 5 '18 at 15:18





    Thanks. I updated the link in my question to relfect the changes on their webpage. Now it should work again.

    – majom
    Mar 5 '18 at 15:18













    I really need to start using the sf package. This is awesome!

    – spacedSparking
    Mar 23 '18 at 20:41





    I really need to start using the sf package. This is awesome!

    – spacedSparking
    Mar 23 '18 at 20:41













    Is there an easy way to only plot the grid cells that intersect with the state polygon?

    – spacedSparking
    Mar 23 '18 at 22:09





    Is there an easy way to only plot the grid cells that intersect with the state polygon?

    – spacedSparking
    Mar 23 '18 at 22:09













    st_intersection(grid_50, nc) should do it

    – sebdalgarno
    Mar 24 '18 at 23:18





    st_intersection(grid_50, nc) should do it

    – sebdalgarno
    Mar 24 '18 at 23:18











    2














    Have you looked at the R raster package? It has tools to convert to/from vector GIS objects so you should be able to a) create a raster (grid) with 200x200m cells and b) convert it to a set of polygons with a logical id of some kind. From there I would look at the sp package to help with intersecting the points and the polygon grid. This http://cran.r-project.org/web/packages/sp/vignettes/over.pdf page might be a good start. Wandering through the sp package docs you might be able to start with the SpatialGrid-class and just skip the raster part entirely.






    share|improve this answer



















    • 1





      Thanks for your comment. I already looked at those packages, but failed to implement this. This was why I was asking for an example.

      – majom
      Mar 10 '14 at 9:05
















    2














    Have you looked at the R raster package? It has tools to convert to/from vector GIS objects so you should be able to a) create a raster (grid) with 200x200m cells and b) convert it to a set of polygons with a logical id of some kind. From there I would look at the sp package to help with intersecting the points and the polygon grid. This http://cran.r-project.org/web/packages/sp/vignettes/over.pdf page might be a good start. Wandering through the sp package docs you might be able to start with the SpatialGrid-class and just skip the raster part entirely.






    share|improve this answer



















    • 1





      Thanks for your comment. I already looked at those packages, but failed to implement this. This was why I was asking for an example.

      – majom
      Mar 10 '14 at 9:05














    2












    2








    2







    Have you looked at the R raster package? It has tools to convert to/from vector GIS objects so you should be able to a) create a raster (grid) with 200x200m cells and b) convert it to a set of polygons with a logical id of some kind. From there I would look at the sp package to help with intersecting the points and the polygon grid. This http://cran.r-project.org/web/packages/sp/vignettes/over.pdf page might be a good start. Wandering through the sp package docs you might be able to start with the SpatialGrid-class and just skip the raster part entirely.






    share|improve this answer













    Have you looked at the R raster package? It has tools to convert to/from vector GIS objects so you should be able to a) create a raster (grid) with 200x200m cells and b) convert it to a set of polygons with a logical id of some kind. From there I would look at the sp package to help with intersecting the points and the polygon grid. This http://cran.r-project.org/web/packages/sp/vignettes/over.pdf page might be a good start. Wandering through the sp package docs you might be able to start with the SpatialGrid-class and just skip the raster part entirely.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Mar 10 '14 at 4:25









    cokrzyscokrzys

    44426




    44426








    • 1





      Thanks for your comment. I already looked at those packages, but failed to implement this. This was why I was asking for an example.

      – majom
      Mar 10 '14 at 9:05














    • 1





      Thanks for your comment. I already looked at those packages, but failed to implement this. This was why I was asking for an example.

      – majom
      Mar 10 '14 at 9:05








    1




    1





    Thanks for your comment. I already looked at those packages, but failed to implement this. This was why I was asking for an example.

    – majom
    Mar 10 '14 at 9:05





    Thanks for your comment. I already looked at those packages, but failed to implement this. This was why I was asking for an example.

    – majom
    Mar 10 '14 at 9:05











    0














    The "GIS universe" is complex and have many standards that your data must be compliant. All "GIS tools" interoperates by GIS-standards. All "serious GIS data" today (2014) are stored in a database.



    The best way to "use R" in a GIS context, with other FOSS tools, is embedded into SQL. The best tools are PostgreSQL 9.X (see PL/R) and PostGIS.





    You answer:




    • To import/export shape files: use shp2pgsql and pgsql2shp.

    • To "split a shape file in 200 meter squares/sub-polygons": see ST_SnapToGrid(), ST_AsRaster(), etc. We need understand better your needs to express into a "recipe".

    • you say that need "geographic coordinates are located" .. perhaps ST_Centroid() of the squares (?)... You can express "more mathematically" so I understand.


    ... Perhaps you not need any raster convertion, only a matrix of regurlar-sampled points.





    A primitive way is use R without PL/R, in a your usual external compiler: only convert your polygons and export as shape or as WKT (see ST_AsText), then convert data with awk or another filter to the R format.






    share|improve this answer





















    • 1





      Thanks for your help. However, I would strongly prefer a solution which relies completely on R and existing packages. When I am able to split the shape file in 200m*200m subpolygons I can check with point.in.polygon which coordinates are in which polygons. My problem is to split the original shapefile in those sub-polygons.

      – majom
      Mar 9 '14 at 21:38













    • It is not a "SIG problem", try to ask at Stackoverflow directly.

      – Peter Krauss
      Mar 10 '14 at 11:18











    • See also how to deal with points of type SpatialPointsDataFrame, and a grid that is a raster at Stackoverflow.

      – Peter Krauss
      Mar 22 '14 at 7:54
















    0














    The "GIS universe" is complex and have many standards that your data must be compliant. All "GIS tools" interoperates by GIS-standards. All "serious GIS data" today (2014) are stored in a database.



    The best way to "use R" in a GIS context, with other FOSS tools, is embedded into SQL. The best tools are PostgreSQL 9.X (see PL/R) and PostGIS.





    You answer:




    • To import/export shape files: use shp2pgsql and pgsql2shp.

    • To "split a shape file in 200 meter squares/sub-polygons": see ST_SnapToGrid(), ST_AsRaster(), etc. We need understand better your needs to express into a "recipe".

    • you say that need "geographic coordinates are located" .. perhaps ST_Centroid() of the squares (?)... You can express "more mathematically" so I understand.


    ... Perhaps you not need any raster convertion, only a matrix of regurlar-sampled points.





    A primitive way is use R without PL/R, in a your usual external compiler: only convert your polygons and export as shape or as WKT (see ST_AsText), then convert data with awk or another filter to the R format.






    share|improve this answer





















    • 1





      Thanks for your help. However, I would strongly prefer a solution which relies completely on R and existing packages. When I am able to split the shape file in 200m*200m subpolygons I can check with point.in.polygon which coordinates are in which polygons. My problem is to split the original shapefile in those sub-polygons.

      – majom
      Mar 9 '14 at 21:38













    • It is not a "SIG problem", try to ask at Stackoverflow directly.

      – Peter Krauss
      Mar 10 '14 at 11:18











    • See also how to deal with points of type SpatialPointsDataFrame, and a grid that is a raster at Stackoverflow.

      – Peter Krauss
      Mar 22 '14 at 7:54














    0












    0








    0







    The "GIS universe" is complex and have many standards that your data must be compliant. All "GIS tools" interoperates by GIS-standards. All "serious GIS data" today (2014) are stored in a database.



    The best way to "use R" in a GIS context, with other FOSS tools, is embedded into SQL. The best tools are PostgreSQL 9.X (see PL/R) and PostGIS.





    You answer:




    • To import/export shape files: use shp2pgsql and pgsql2shp.

    • To "split a shape file in 200 meter squares/sub-polygons": see ST_SnapToGrid(), ST_AsRaster(), etc. We need understand better your needs to express into a "recipe".

    • you say that need "geographic coordinates are located" .. perhaps ST_Centroid() of the squares (?)... You can express "more mathematically" so I understand.


    ... Perhaps you not need any raster convertion, only a matrix of regurlar-sampled points.





    A primitive way is use R without PL/R, in a your usual external compiler: only convert your polygons and export as shape or as WKT (see ST_AsText), then convert data with awk or another filter to the R format.






    share|improve this answer















    The "GIS universe" is complex and have many standards that your data must be compliant. All "GIS tools" interoperates by GIS-standards. All "serious GIS data" today (2014) are stored in a database.



    The best way to "use R" in a GIS context, with other FOSS tools, is embedded into SQL. The best tools are PostgreSQL 9.X (see PL/R) and PostGIS.





    You answer:




    • To import/export shape files: use shp2pgsql and pgsql2shp.

    • To "split a shape file in 200 meter squares/sub-polygons": see ST_SnapToGrid(), ST_AsRaster(), etc. We need understand better your needs to express into a "recipe".

    • you say that need "geographic coordinates are located" .. perhaps ST_Centroid() of the squares (?)... You can express "more mathematically" so I understand.


    ... Perhaps you not need any raster convertion, only a matrix of regurlar-sampled points.





    A primitive way is use R without PL/R, in a your usual external compiler: only convert your polygons and export as shape or as WKT (see ST_AsText), then convert data with awk or another filter to the R format.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Apr 13 '17 at 12:33









    Community

    1




    1










    answered Mar 9 '14 at 21:20









    Peter KraussPeter Krauss

    1,1071434




    1,1071434








    • 1





      Thanks for your help. However, I would strongly prefer a solution which relies completely on R and existing packages. When I am able to split the shape file in 200m*200m subpolygons I can check with point.in.polygon which coordinates are in which polygons. My problem is to split the original shapefile in those sub-polygons.

      – majom
      Mar 9 '14 at 21:38













    • It is not a "SIG problem", try to ask at Stackoverflow directly.

      – Peter Krauss
      Mar 10 '14 at 11:18











    • See also how to deal with points of type SpatialPointsDataFrame, and a grid that is a raster at Stackoverflow.

      – Peter Krauss
      Mar 22 '14 at 7:54














    • 1





      Thanks for your help. However, I would strongly prefer a solution which relies completely on R and existing packages. When I am able to split the shape file in 200m*200m subpolygons I can check with point.in.polygon which coordinates are in which polygons. My problem is to split the original shapefile in those sub-polygons.

      – majom
      Mar 9 '14 at 21:38













    • It is not a "SIG problem", try to ask at Stackoverflow directly.

      – Peter Krauss
      Mar 10 '14 at 11:18











    • See also how to deal with points of type SpatialPointsDataFrame, and a grid that is a raster at Stackoverflow.

      – Peter Krauss
      Mar 22 '14 at 7:54








    1




    1





    Thanks for your help. However, I would strongly prefer a solution which relies completely on R and existing packages. When I am able to split the shape file in 200m*200m subpolygons I can check with point.in.polygon which coordinates are in which polygons. My problem is to split the original shapefile in those sub-polygons.

    – majom
    Mar 9 '14 at 21:38







    Thanks for your help. However, I would strongly prefer a solution which relies completely on R and existing packages. When I am able to split the shape file in 200m*200m subpolygons I can check with point.in.polygon which coordinates are in which polygons. My problem is to split the original shapefile in those sub-polygons.

    – majom
    Mar 9 '14 at 21:38















    It is not a "SIG problem", try to ask at Stackoverflow directly.

    – Peter Krauss
    Mar 10 '14 at 11:18





    It is not a "SIG problem", try to ask at Stackoverflow directly.

    – Peter Krauss
    Mar 10 '14 at 11:18













    See also how to deal with points of type SpatialPointsDataFrame, and a grid that is a raster at Stackoverflow.

    – Peter Krauss
    Mar 22 '14 at 7:54





    See also how to deal with points of type SpatialPointsDataFrame, and a grid that is a raster at Stackoverflow.

    – Peter Krauss
    Mar 22 '14 at 7:54











    0














    Is there way to dropping empty grids? or just griding the boundary of interest?






    share|improve this answer








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      Is there way to dropping empty grids? or just griding the boundary of interest?






      share|improve this answer








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        0












        0








        0







        Is there way to dropping empty grids? or just griding the boundary of interest?






        share|improve this answer








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        Is there way to dropping empty grids? or just griding the boundary of interest?







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        answered 14 mins ago









        NeedHelpNeedHelp

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