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Is there a file that always exists and a 'normal' user can't lstat it?
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I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)
The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)
Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.
EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.
linux ubuntu
add a comment |
I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)
The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)
Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.
EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.
linux ubuntu
1
IMHO/etc/shadow
– Romeo Ninov
34 mins ago
@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?
– Crouching Kitten
30 mins ago
1
You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then/proc/1/fd/0
should do.
– mosvy
15 mins ago
1
@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.
– Crouching Kitten
12 mins ago
add a comment |
I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)
The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)
Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.
EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.
linux ubuntu
I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)
The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)
Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.
EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.
linux ubuntu
linux ubuntu
edited 20 mins ago
Crouching Kitten
asked 37 mins ago
Crouching KittenCrouching Kitten
268310
268310
1
IMHO/etc/shadow
– Romeo Ninov
34 mins ago
@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?
– Crouching Kitten
30 mins ago
1
You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then/proc/1/fd/0
should do.
– mosvy
15 mins ago
1
@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.
– Crouching Kitten
12 mins ago
add a comment |
1
IMHO/etc/shadow
– Romeo Ninov
34 mins ago
@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?
– Crouching Kitten
30 mins ago
1
You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then/proc/1/fd/0
should do.
– mosvy
15 mins ago
1
@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.
– Crouching Kitten
12 mins ago
1
1
IMHO
/etc/shadow
– Romeo Ninov
34 mins ago
IMHO
/etc/shadow
– Romeo Ninov
34 mins ago
@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?
– Crouching Kitten
30 mins ago
@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?
– Crouching Kitten
30 mins ago
1
1
You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then
/proc/1/fd/0
should do.– mosvy
15 mins ago
You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then
/proc/1/fd/0
should do.– mosvy
15 mins ago
1
1
@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.
– Crouching Kitten
12 mins ago
@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.
– Crouching Kitten
12 mins ago
add a comment |
3 Answers
3
active
oldest
votes
On modern Linux systems, you should be able to use /proc/1/fdinfo/0
(information for the file descriptor 1 (stdout) of the process of id 1 (init
in the root pid namespace which should be running as root
)).
You can find a list with (zsh
or bash
syntax):
sudo find /etc /dev /sys /proc -type f -print0 |
while IFS= read -rd '' f; do
[ -e "$f" ] || printf '%sn' "$f"
done
(remove -type f
if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ]
to [ -e "$f" ] || [ -L "$f" ]
or use zsh
's stat -L
builtin instead of [
).
Thanks! If/proc/1/fdinfo/0
works on Ubuntu 16.04 and 18.04, that's more than enough.
– Crouching Kitten
10 mins ago
add a comment |
You can find
it yourself.
Using /etc
-- the configuration files directory as a starting point:
sudo find /etc -type f -perm 0400 -user root
On my system, this does not return anything.
You can be a less restrictive and allow group root
(only user root
should be a member of group root
), and a look out for a permission of 440
:
sudo find /etc -perm 0440 -user root -group root
On my system this returns:
/etc/sudoers.d/README
/etc/sudoers
Edit:
Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:
sudo find / -perm o-rwx -user root -group root
here i'm looking for directories (type d
) that lacks the read-write-execute perm bits for others (o-rwx
) and is owned by root:root
.
Technically, just the absense of read (r
) bit would prevent a directory listing (lstat(2)
) on directory.
In the output i've found /run/systemd/inaccessible/
on my Systemd init based system.
Regarding files in /proc
, /sys
, /dev
:
These filesystems are virtual FS (
tmpfs
) i.e. they reside on memory, not on diskIf you plan to rely on
/proc
, use/proc/1/
i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.
Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)
– Crouching Kitten
28 mins ago
Thanks. Withfind / -type d -perm 0400 -user root
I have found the directory/proc/20/map_files/
, if I refer to a made-up file name inside that folder, like/proc/20/map_files/asdasd
, then it always fails. Does that folder always exist on Ubuntu?
– Crouching Kitten
15 mins ago
@CrouchingKitten, the directories in/proc/1/
might be safer, since init always exists. But that'sproc
, not a regular filesystem, in case it matters.
– ilkkachu
9 mins ago
Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that/proc/1/fdinfo/0
works on modern Ubuntus.
– Crouching Kitten
6 mins ago
add a comment |
Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)
The most obvious one is:
EACCES
Search permission is denied for one of the directories in the path prefix of path.
So you need a directory you can't read from.
Yes, you can look for one that's already in your system (perhaps /var/lib/private
if it exists?) But you might as well create one yourself, with the equivalent of:
$ mkdir myprivatedir
$ touch myprivatedir/myunreachablefile
$ chmod 0 myprivatedir
$ ls -l myprivatedir/myunreachablefile
The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x
removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)
There's another creative way to make lstat(2) fail, looking at its man page:
ENOTDIR
A component of the path prefix of path is not a directory.
So, trying to access a file such as /etc/passwd/nonexistent
should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.
Another one is:
ENAMETOOLONG
path is too long.
But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)
Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e
or the equivalent [ -e ...]
from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
On modern Linux systems, you should be able to use /proc/1/fdinfo/0
(information for the file descriptor 1 (stdout) of the process of id 1 (init
in the root pid namespace which should be running as root
)).
You can find a list with (zsh
or bash
syntax):
sudo find /etc /dev /sys /proc -type f -print0 |
while IFS= read -rd '' f; do
[ -e "$f" ] || printf '%sn' "$f"
done
(remove -type f
if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ]
to [ -e "$f" ] || [ -L "$f" ]
or use zsh
's stat -L
builtin instead of [
).
Thanks! If/proc/1/fdinfo/0
works on Ubuntu 16.04 and 18.04, that's more than enough.
– Crouching Kitten
10 mins ago
add a comment |
On modern Linux systems, you should be able to use /proc/1/fdinfo/0
(information for the file descriptor 1 (stdout) of the process of id 1 (init
in the root pid namespace which should be running as root
)).
You can find a list with (zsh
or bash
syntax):
sudo find /etc /dev /sys /proc -type f -print0 |
while IFS= read -rd '' f; do
[ -e "$f" ] || printf '%sn' "$f"
done
(remove -type f
if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ]
to [ -e "$f" ] || [ -L "$f" ]
or use zsh
's stat -L
builtin instead of [
).
Thanks! If/proc/1/fdinfo/0
works on Ubuntu 16.04 and 18.04, that's more than enough.
– Crouching Kitten
10 mins ago
add a comment |
On modern Linux systems, you should be able to use /proc/1/fdinfo/0
(information for the file descriptor 1 (stdout) of the process of id 1 (init
in the root pid namespace which should be running as root
)).
You can find a list with (zsh
or bash
syntax):
sudo find /etc /dev /sys /proc -type f -print0 |
while IFS= read -rd '' f; do
[ -e "$f" ] || printf '%sn' "$f"
done
(remove -type f
if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ]
to [ -e "$f" ] || [ -L "$f" ]
or use zsh
's stat -L
builtin instead of [
).
On modern Linux systems, you should be able to use /proc/1/fdinfo/0
(information for the file descriptor 1 (stdout) of the process of id 1 (init
in the root pid namespace which should be running as root
)).
You can find a list with (zsh
or bash
syntax):
sudo find /etc /dev /sys /proc -type f -print0 |
while IFS= read -rd '' f; do
[ -e "$f" ] || printf '%sn' "$f"
done
(remove -type f
if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ]
to [ -e "$f" ] || [ -L "$f" ]
or use zsh
's stat -L
builtin instead of [
).
edited 9 mins ago
answered 12 mins ago
Stéphane ChazelasStéphane Chazelas
307k57581936
307k57581936
Thanks! If/proc/1/fdinfo/0
works on Ubuntu 16.04 and 18.04, that's more than enough.
– Crouching Kitten
10 mins ago
add a comment |
Thanks! If/proc/1/fdinfo/0
works on Ubuntu 16.04 and 18.04, that's more than enough.
– Crouching Kitten
10 mins ago
Thanks! If
/proc/1/fdinfo/0
works on Ubuntu 16.04 and 18.04, that's more than enough.– Crouching Kitten
10 mins ago
Thanks! If
/proc/1/fdinfo/0
works on Ubuntu 16.04 and 18.04, that's more than enough.– Crouching Kitten
10 mins ago
add a comment |
You can find
it yourself.
Using /etc
-- the configuration files directory as a starting point:
sudo find /etc -type f -perm 0400 -user root
On my system, this does not return anything.
You can be a less restrictive and allow group root
(only user root
should be a member of group root
), and a look out for a permission of 440
:
sudo find /etc -perm 0440 -user root -group root
On my system this returns:
/etc/sudoers.d/README
/etc/sudoers
Edit:
Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:
sudo find / -perm o-rwx -user root -group root
here i'm looking for directories (type d
) that lacks the read-write-execute perm bits for others (o-rwx
) and is owned by root:root
.
Technically, just the absense of read (r
) bit would prevent a directory listing (lstat(2)
) on directory.
In the output i've found /run/systemd/inaccessible/
on my Systemd init based system.
Regarding files in /proc
, /sys
, /dev
:
These filesystems are virtual FS (
tmpfs
) i.e. they reside on memory, not on diskIf you plan to rely on
/proc
, use/proc/1/
i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.
Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)
– Crouching Kitten
28 mins ago
Thanks. Withfind / -type d -perm 0400 -user root
I have found the directory/proc/20/map_files/
, if I refer to a made-up file name inside that folder, like/proc/20/map_files/asdasd
, then it always fails. Does that folder always exist on Ubuntu?
– Crouching Kitten
15 mins ago
@CrouchingKitten, the directories in/proc/1/
might be safer, since init always exists. But that'sproc
, not a regular filesystem, in case it matters.
– ilkkachu
9 mins ago
Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that/proc/1/fdinfo/0
works on modern Ubuntus.
– Crouching Kitten
6 mins ago
add a comment |
You can find
it yourself.
Using /etc
-- the configuration files directory as a starting point:
sudo find /etc -type f -perm 0400 -user root
On my system, this does not return anything.
You can be a less restrictive and allow group root
(only user root
should be a member of group root
), and a look out for a permission of 440
:
sudo find /etc -perm 0440 -user root -group root
On my system this returns:
/etc/sudoers.d/README
/etc/sudoers
Edit:
Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:
sudo find / -perm o-rwx -user root -group root
here i'm looking for directories (type d
) that lacks the read-write-execute perm bits for others (o-rwx
) and is owned by root:root
.
Technically, just the absense of read (r
) bit would prevent a directory listing (lstat(2)
) on directory.
In the output i've found /run/systemd/inaccessible/
on my Systemd init based system.
Regarding files in /proc
, /sys
, /dev
:
These filesystems are virtual FS (
tmpfs
) i.e. they reside on memory, not on diskIf you plan to rely on
/proc
, use/proc/1/
i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.
Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)
– Crouching Kitten
28 mins ago
Thanks. Withfind / -type d -perm 0400 -user root
I have found the directory/proc/20/map_files/
, if I refer to a made-up file name inside that folder, like/proc/20/map_files/asdasd
, then it always fails. Does that folder always exist on Ubuntu?
– Crouching Kitten
15 mins ago
@CrouchingKitten, the directories in/proc/1/
might be safer, since init always exists. But that'sproc
, not a regular filesystem, in case it matters.
– ilkkachu
9 mins ago
Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that/proc/1/fdinfo/0
works on modern Ubuntus.
– Crouching Kitten
6 mins ago
add a comment |
You can find
it yourself.
Using /etc
-- the configuration files directory as a starting point:
sudo find /etc -type f -perm 0400 -user root
On my system, this does not return anything.
You can be a less restrictive and allow group root
(only user root
should be a member of group root
), and a look out for a permission of 440
:
sudo find /etc -perm 0440 -user root -group root
On my system this returns:
/etc/sudoers.d/README
/etc/sudoers
Edit:
Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:
sudo find / -perm o-rwx -user root -group root
here i'm looking for directories (type d
) that lacks the read-write-execute perm bits for others (o-rwx
) and is owned by root:root
.
Technically, just the absense of read (r
) bit would prevent a directory listing (lstat(2)
) on directory.
In the output i've found /run/systemd/inaccessible/
on my Systemd init based system.
Regarding files in /proc
, /sys
, /dev
:
These filesystems are virtual FS (
tmpfs
) i.e. they reside on memory, not on diskIf you plan to rely on
/proc
, use/proc/1/
i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.
You can find
it yourself.
Using /etc
-- the configuration files directory as a starting point:
sudo find /etc -type f -perm 0400 -user root
On my system, this does not return anything.
You can be a less restrictive and allow group root
(only user root
should be a member of group root
), and a look out for a permission of 440
:
sudo find /etc -perm 0440 -user root -group root
On my system this returns:
/etc/sudoers.d/README
/etc/sudoers
Edit:
Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:
sudo find / -perm o-rwx -user root -group root
here i'm looking for directories (type d
) that lacks the read-write-execute perm bits for others (o-rwx
) and is owned by root:root
.
Technically, just the absense of read (r
) bit would prevent a directory listing (lstat(2)
) on directory.
In the output i've found /run/systemd/inaccessible/
on my Systemd init based system.
Regarding files in /proc
, /sys
, /dev
:
These filesystems are virtual FS (
tmpfs
) i.e. they reside on memory, not on diskIf you plan to rely on
/proc
, use/proc/1/
i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.
edited 3 mins ago
answered 31 mins ago
heemaylheemayl
35.6k376105
35.6k376105
Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)
– Crouching Kitten
28 mins ago
Thanks. Withfind / -type d -perm 0400 -user root
I have found the directory/proc/20/map_files/
, if I refer to a made-up file name inside that folder, like/proc/20/map_files/asdasd
, then it always fails. Does that folder always exist on Ubuntu?
– Crouching Kitten
15 mins ago
@CrouchingKitten, the directories in/proc/1/
might be safer, since init always exists. But that'sproc
, not a regular filesystem, in case it matters.
– ilkkachu
9 mins ago
Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that/proc/1/fdinfo/0
works on modern Ubuntus.
– Crouching Kitten
6 mins ago
add a comment |
Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)
– Crouching Kitten
28 mins ago
Thanks. Withfind / -type d -perm 0400 -user root
I have found the directory/proc/20/map_files/
, if I refer to a made-up file name inside that folder, like/proc/20/map_files/asdasd
, then it always fails. Does that folder always exist on Ubuntu?
– Crouching Kitten
15 mins ago
@CrouchingKitten, the directories in/proc/1/
might be safer, since init always exists. But that'sproc
, not a regular filesystem, in case it matters.
– ilkkachu
9 mins ago
Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that/proc/1/fdinfo/0
works on modern Ubuntus.
– Crouching Kitten
6 mins ago
Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)
– Crouching Kitten
28 mins ago
Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)
– Crouching Kitten
28 mins ago
Thanks. With
find / -type d -perm 0400 -user root
I have found the directory /proc/20/map_files/
, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd
, then it always fails. Does that folder always exist on Ubuntu?– Crouching Kitten
15 mins ago
Thanks. With
find / -type d -perm 0400 -user root
I have found the directory /proc/20/map_files/
, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd
, then it always fails. Does that folder always exist on Ubuntu?– Crouching Kitten
15 mins ago
@CrouchingKitten, the directories in
/proc/1/
might be safer, since init always exists. But that's proc
, not a regular filesystem, in case it matters.– ilkkachu
9 mins ago
@CrouchingKitten, the directories in
/proc/1/
might be safer, since init always exists. But that's proc
, not a regular filesystem, in case it matters.– ilkkachu
9 mins ago
Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that
/proc/1/fdinfo/0
works on modern Ubuntus.– Crouching Kitten
6 mins ago
Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that
/proc/1/fdinfo/0
works on modern Ubuntus.– Crouching Kitten
6 mins ago
add a comment |
Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)
The most obvious one is:
EACCES
Search permission is denied for one of the directories in the path prefix of path.
So you need a directory you can't read from.
Yes, you can look for one that's already in your system (perhaps /var/lib/private
if it exists?) But you might as well create one yourself, with the equivalent of:
$ mkdir myprivatedir
$ touch myprivatedir/myunreachablefile
$ chmod 0 myprivatedir
$ ls -l myprivatedir/myunreachablefile
The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x
removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)
There's another creative way to make lstat(2) fail, looking at its man page:
ENOTDIR
A component of the path prefix of path is not a directory.
So, trying to access a file such as /etc/passwd/nonexistent
should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.
Another one is:
ENAMETOOLONG
path is too long.
But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)
Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e
or the equivalent [ -e ...]
from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.
add a comment |
Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)
The most obvious one is:
EACCES
Search permission is denied for one of the directories in the path prefix of path.
So you need a directory you can't read from.
Yes, you can look for one that's already in your system (perhaps /var/lib/private
if it exists?) But you might as well create one yourself, with the equivalent of:
$ mkdir myprivatedir
$ touch myprivatedir/myunreachablefile
$ chmod 0 myprivatedir
$ ls -l myprivatedir/myunreachablefile
The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x
removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)
There's another creative way to make lstat(2) fail, looking at its man page:
ENOTDIR
A component of the path prefix of path is not a directory.
So, trying to access a file such as /etc/passwd/nonexistent
should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.
Another one is:
ENAMETOOLONG
path is too long.
But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)
Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e
or the equivalent [ -e ...]
from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.
add a comment |
Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)
The most obvious one is:
EACCES
Search permission is denied for one of the directories in the path prefix of path.
So you need a directory you can't read from.
Yes, you can look for one that's already in your system (perhaps /var/lib/private
if it exists?) But you might as well create one yourself, with the equivalent of:
$ mkdir myprivatedir
$ touch myprivatedir/myunreachablefile
$ chmod 0 myprivatedir
$ ls -l myprivatedir/myunreachablefile
The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x
removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)
There's another creative way to make lstat(2) fail, looking at its man page:
ENOTDIR
A component of the path prefix of path is not a directory.
So, trying to access a file such as /etc/passwd/nonexistent
should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.
Another one is:
ENAMETOOLONG
path is too long.
But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)
Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e
or the equivalent [ -e ...]
from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.
Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)
The most obvious one is:
EACCES
Search permission is denied for one of the directories in the path prefix of path.
So you need a directory you can't read from.
Yes, you can look for one that's already in your system (perhaps /var/lib/private
if it exists?) But you might as well create one yourself, with the equivalent of:
$ mkdir myprivatedir
$ touch myprivatedir/myunreachablefile
$ chmod 0 myprivatedir
$ ls -l myprivatedir/myunreachablefile
The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x
removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)
There's another creative way to make lstat(2) fail, looking at its man page:
ENOTDIR
A component of the path prefix of path is not a directory.
So, trying to access a file such as /etc/passwd/nonexistent
should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.
Another one is:
ENAMETOOLONG
path is too long.
But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)
Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e
or the equivalent [ -e ...]
from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.
answered 4 mins ago
filbrandenfilbranden
9,21621342
9,21621342
add a comment |
add a comment |
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1
IMHO
/etc/shadow
– Romeo Ninov
34 mins ago
@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?
– Crouching Kitten
30 mins ago
1
You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then
/proc/1/fd/0
should do.– mosvy
15 mins ago
1
@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.
– Crouching Kitten
12 mins ago