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Is there a file that always exists and a 'normal' user can't lstat it?


Make all files under a directory read-only without changing permissions?Setting up a shared folder with group: ACL and file creationMonitor file access count by userChanging user to root when connected to a linux server and copying filesHow to remount as read-write a specific mount of device?Linux user groups and file system permissionsSyslog config syntaxAccess to the internet from a firewalled serverhwclock can't open rtc fileGive read permission to non-root user for root owned file?













3















I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)



The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)



Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.



EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.










share|improve this question




















  • 1





    IMHO /etc/shadow

    – Romeo Ninov
    34 mins ago











  • @RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?

    – Crouching Kitten
    30 mins ago






  • 1





    You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then /proc/1/fd/0 should do.

    – mosvy
    15 mins ago








  • 1





    @mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.

    – Crouching Kitten
    12 mins ago
















3















I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)



The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)



Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.



EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.










share|improve this question




















  • 1





    IMHO /etc/shadow

    – Romeo Ninov
    34 mins ago











  • @RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?

    – Crouching Kitten
    30 mins ago






  • 1





    You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then /proc/1/fd/0 should do.

    – mosvy
    15 mins ago








  • 1





    @mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.

    – Crouching Kitten
    12 mins ago














3












3








3








I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)



The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)



Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.



EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.










share|improve this question
















I need this for a unit test. There's a function, which does lstat on the file path passed in its parameter. I have to trigger the code path when the lstat fails. (Because the code coverage has to reach 90%)



The test can run only under a single user, therefore I was thinking if there's a file in Ubuntu, which always exists but normal users have no read access to it, or its folder. (So lstat would fail on it unless executed as root.)



Non-existing file is not a solution, because there's a separate code path for that, which I'm already triggering.



EDIT: Lack of read access to the file only is not enough. With that lstat can still be executed. I was able to trigger it (on my local machine, where I have root access), by creating a folder in /root, and a file in it. And setting permission 700 on the folder. So I'm searching for a file, which is in a folder that is only accessible by root.







linux ubuntu






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 20 mins ago







Crouching Kitten

















asked 37 mins ago









Crouching KittenCrouching Kitten

268310




268310








  • 1





    IMHO /etc/shadow

    – Romeo Ninov
    34 mins ago











  • @RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?

    – Crouching Kitten
    30 mins ago






  • 1





    You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then /proc/1/fd/0 should do.

    – mosvy
    15 mins ago








  • 1





    @mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.

    – Crouching Kitten
    12 mins ago














  • 1





    IMHO /etc/shadow

    – Romeo Ninov
    34 mins ago











  • @RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?

    – Crouching Kitten
    30 mins ago






  • 1





    You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then /proc/1/fd/0 should do.

    – mosvy
    15 mins ago








  • 1





    @mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.

    – Crouching Kitten
    12 mins ago








1




1





IMHO /etc/shadow

– Romeo Ninov
34 mins ago





IMHO /etc/shadow

– Romeo Ninov
34 mins ago













@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?

– Crouching Kitten
30 mins ago





@RomeoNinov thanks. Maybe my question is wrong. That file is readable, but I can lstat it. Then its directory has to be non-readable?

– Crouching Kitten
30 mins ago




1




1





You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then /proc/1/fd/0 should do.

– mosvy
15 mins ago







You cannot assume the existence of any file, because your program may run in a chroot or separate namespace. If assuming that /proc is mounted is OK and init is nothing special, then /proc/1/fd/0 should do.

– mosvy
15 mins ago






1




1





@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.

– Crouching Kitten
12 mins ago





@mosvy Thanks that works on my local machine. Hmm then I'll try it on the QA and Staging pool too.

– Crouching Kitten
12 mins ago










3 Answers
3






active

oldest

votes


















2














On modern Linux systems, you should be able to use /proc/1/fdinfo/0 (information for the file descriptor 1 (stdout) of the process of id 1 (init in the root pid namespace which should be running as root)).



You can find a list with (zsh or bash syntax):



sudo find /etc /dev /sys /proc -type f -print0 |
while IFS= read -rd '' f; do
[ -e "$f" ] || printf '%sn' "$f"
done


(remove -type f if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ] to [ -e "$f" ] || [ -L "$f" ] or use zsh's stat -L builtin instead of [).






share|improve this answer


























  • Thanks! If /proc/1/fdinfo/0 works on Ubuntu 16.04 and 18.04, that's more than enough.

    – Crouching Kitten
    10 mins ago



















3














You can find it yourself.



Using /etc -- the configuration files directory as a starting point:



sudo find /etc -type f -perm 0400 -user root


On my system, this does not return anything.



You can be a less restrictive and allow group root (only user root should be a member of group root), and a look out for a permission of 440:



sudo find /etc -perm 0440 -user root -group root


On my system this returns:



/etc/sudoers.d/README
/etc/sudoers




Edit:



Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:



sudo find / -perm o-rwx -user root -group root 


here i'm looking for directories (type d) that lacks the read-write-execute perm bits for others (o-rwx) and is owned by root:root.



Technically, just the absense of read (r) bit would prevent a directory listing (lstat(2)) on directory.



In the output i've found /run/systemd/inaccessible/ on my Systemd init based system.



Regarding files in /proc, /sys, /dev:




  • These filesystems are virtual FS (tmpfs) i.e. they reside on memory, not on disk


  • If you plan to rely on /proc, use /proc/1/ i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.







share|improve this answer


























  • Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)

    – Crouching Kitten
    28 mins ago













  • Thanks. With find / -type d -perm 0400 -user root I have found the directory /proc/20/map_files/, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd, then it always fails. Does that folder always exist on Ubuntu?

    – Crouching Kitten
    15 mins ago











  • @CrouchingKitten, the directories in /proc/1/ might be safer, since init always exists. But that's proc, not a regular filesystem, in case it matters.

    – ilkkachu
    9 mins ago











  • Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that /proc/1/fdinfo/0 works on modern Ubuntus.

    – Crouching Kitten
    6 mins ago





















1














Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)



The most obvious one is:




EACCES
Search permission is denied for one of the directories in the path prefix of path.




So you need a directory you can't read from.



Yes, you can look for one that's already in your system (perhaps /var/lib/private if it exists?) But you might as well create one yourself, with the equivalent of:



$ mkdir myprivatedir
$ touch myprivatedir/myunreachablefile
$ chmod 0 myprivatedir
$ ls -l myprivatedir/myunreachablefile


The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)



There's another creative way to make lstat(2) fail, looking at its man page:




ENOTDIR
A component of the path prefix of path is not a directory.




So, trying to access a file such as /etc/passwd/nonexistent should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.



Another one is:




ENAMETOOLONG
path is too long.




But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)



Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e or the equivalent [ -e ...] from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.





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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    On modern Linux systems, you should be able to use /proc/1/fdinfo/0 (information for the file descriptor 1 (stdout) of the process of id 1 (init in the root pid namespace which should be running as root)).



    You can find a list with (zsh or bash syntax):



    sudo find /etc /dev /sys /proc -type f -print0 |
    while IFS= read -rd '' f; do
    [ -e "$f" ] || printf '%sn' "$f"
    done


    (remove -type f if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ] to [ -e "$f" ] || [ -L "$f" ] or use zsh's stat -L builtin instead of [).






    share|improve this answer


























    • Thanks! If /proc/1/fdinfo/0 works on Ubuntu 16.04 and 18.04, that's more than enough.

      – Crouching Kitten
      10 mins ago
















    2














    On modern Linux systems, you should be able to use /proc/1/fdinfo/0 (information for the file descriptor 1 (stdout) of the process of id 1 (init in the root pid namespace which should be running as root)).



    You can find a list with (zsh or bash syntax):



    sudo find /etc /dev /sys /proc -type f -print0 |
    while IFS= read -rd '' f; do
    [ -e "$f" ] || printf '%sn' "$f"
    done


    (remove -type f if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ] to [ -e "$f" ] || [ -L "$f" ] or use zsh's stat -L builtin instead of [).






    share|improve this answer


























    • Thanks! If /proc/1/fdinfo/0 works on Ubuntu 16.04 and 18.04, that's more than enough.

      – Crouching Kitten
      10 mins ago














    2












    2








    2







    On modern Linux systems, you should be able to use /proc/1/fdinfo/0 (information for the file descriptor 1 (stdout) of the process of id 1 (init in the root pid namespace which should be running as root)).



    You can find a list with (zsh or bash syntax):



    sudo find /etc /dev /sys /proc -type f -print0 |
    while IFS= read -rd '' f; do
    [ -e "$f" ] || printf '%sn' "$f"
    done


    (remove -type f if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ] to [ -e "$f" ] || [ -L "$f" ] or use zsh's stat -L builtin instead of [).






    share|improve this answer















    On modern Linux systems, you should be able to use /proc/1/fdinfo/0 (information for the file descriptor 1 (stdout) of the process of id 1 (init in the root pid namespace which should be running as root)).



    You can find a list with (zsh or bash syntax):



    sudo find /etc /dev /sys /proc -type f -print0 |
    while IFS= read -rd '' f; do
    [ -e "$f" ] || printf '%sn' "$f"
    done


    (remove -type f if you don't want to restrict to regular files, but then you'd also need to change [ -e "$f" ] to [ -e "$f" ] || [ -L "$f" ] or use zsh's stat -L builtin instead of [).







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 9 mins ago

























    answered 12 mins ago









    Stéphane ChazelasStéphane Chazelas

    307k57581936




    307k57581936













    • Thanks! If /proc/1/fdinfo/0 works on Ubuntu 16.04 and 18.04, that's more than enough.

      – Crouching Kitten
      10 mins ago



















    • Thanks! If /proc/1/fdinfo/0 works on Ubuntu 16.04 and 18.04, that's more than enough.

      – Crouching Kitten
      10 mins ago

















    Thanks! If /proc/1/fdinfo/0 works on Ubuntu 16.04 and 18.04, that's more than enough.

    – Crouching Kitten
    10 mins ago





    Thanks! If /proc/1/fdinfo/0 works on Ubuntu 16.04 and 18.04, that's more than enough.

    – Crouching Kitten
    10 mins ago













    3














    You can find it yourself.



    Using /etc -- the configuration files directory as a starting point:



    sudo find /etc -type f -perm 0400 -user root


    On my system, this does not return anything.



    You can be a less restrictive and allow group root (only user root should be a member of group root), and a look out for a permission of 440:



    sudo find /etc -perm 0440 -user root -group root


    On my system this returns:



    /etc/sudoers.d/README
    /etc/sudoers




    Edit:



    Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:



    sudo find / -perm o-rwx -user root -group root 


    here i'm looking for directories (type d) that lacks the read-write-execute perm bits for others (o-rwx) and is owned by root:root.



    Technically, just the absense of read (r) bit would prevent a directory listing (lstat(2)) on directory.



    In the output i've found /run/systemd/inaccessible/ on my Systemd init based system.



    Regarding files in /proc, /sys, /dev:




    • These filesystems are virtual FS (tmpfs) i.e. they reside on memory, not on disk


    • If you plan to rely on /proc, use /proc/1/ i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.







    share|improve this answer


























    • Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)

      – Crouching Kitten
      28 mins ago













    • Thanks. With find / -type d -perm 0400 -user root I have found the directory /proc/20/map_files/, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd, then it always fails. Does that folder always exist on Ubuntu?

      – Crouching Kitten
      15 mins ago











    • @CrouchingKitten, the directories in /proc/1/ might be safer, since init always exists. But that's proc, not a regular filesystem, in case it matters.

      – ilkkachu
      9 mins ago











    • Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that /proc/1/fdinfo/0 works on modern Ubuntus.

      – Crouching Kitten
      6 mins ago


















    3














    You can find it yourself.



    Using /etc -- the configuration files directory as a starting point:



    sudo find /etc -type f -perm 0400 -user root


    On my system, this does not return anything.



    You can be a less restrictive and allow group root (only user root should be a member of group root), and a look out for a permission of 440:



    sudo find /etc -perm 0440 -user root -group root


    On my system this returns:



    /etc/sudoers.d/README
    /etc/sudoers




    Edit:



    Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:



    sudo find / -perm o-rwx -user root -group root 


    here i'm looking for directories (type d) that lacks the read-write-execute perm bits for others (o-rwx) and is owned by root:root.



    Technically, just the absense of read (r) bit would prevent a directory listing (lstat(2)) on directory.



    In the output i've found /run/systemd/inaccessible/ on my Systemd init based system.



    Regarding files in /proc, /sys, /dev:




    • These filesystems are virtual FS (tmpfs) i.e. they reside on memory, not on disk


    • If you plan to rely on /proc, use /proc/1/ i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.







    share|improve this answer


























    • Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)

      – Crouching Kitten
      28 mins ago













    • Thanks. With find / -type d -perm 0400 -user root I have found the directory /proc/20/map_files/, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd, then it always fails. Does that folder always exist on Ubuntu?

      – Crouching Kitten
      15 mins ago











    • @CrouchingKitten, the directories in /proc/1/ might be safer, since init always exists. But that's proc, not a regular filesystem, in case it matters.

      – ilkkachu
      9 mins ago











    • Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that /proc/1/fdinfo/0 works on modern Ubuntus.

      – Crouching Kitten
      6 mins ago
















    3












    3








    3







    You can find it yourself.



    Using /etc -- the configuration files directory as a starting point:



    sudo find /etc -type f -perm 0400 -user root


    On my system, this does not return anything.



    You can be a less restrictive and allow group root (only user root should be a member of group root), and a look out for a permission of 440:



    sudo find /etc -perm 0440 -user root -group root


    On my system this returns:



    /etc/sudoers.d/README
    /etc/sudoers




    Edit:



    Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:



    sudo find / -perm o-rwx -user root -group root 


    here i'm looking for directories (type d) that lacks the read-write-execute perm bits for others (o-rwx) and is owned by root:root.



    Technically, just the absense of read (r) bit would prevent a directory listing (lstat(2)) on directory.



    In the output i've found /run/systemd/inaccessible/ on my Systemd init based system.



    Regarding files in /proc, /sys, /dev:




    • These filesystems are virtual FS (tmpfs) i.e. they reside on memory, not on disk


    • If you plan to rely on /proc, use /proc/1/ i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.







    share|improve this answer















    You can find it yourself.



    Using /etc -- the configuration files directory as a starting point:



    sudo find /etc -type f -perm 0400 -user root


    On my system, this does not return anything.



    You can be a less restrictive and allow group root (only user root should be a member of group root), and a look out for a permission of 440:



    sudo find /etc -perm 0440 -user root -group root


    On my system this returns:



    /etc/sudoers.d/README
    /etc/sudoers




    Edit:



    Based on your edit, you're looking for a directory that does not have sufficient permission for the invoking user to prevent directory listing:



    sudo find / -perm o-rwx -user root -group root 


    here i'm looking for directories (type d) that lacks the read-write-execute perm bits for others (o-rwx) and is owned by root:root.



    Technically, just the absense of read (r) bit would prevent a directory listing (lstat(2)) on directory.



    In the output i've found /run/systemd/inaccessible/ on my Systemd init based system.



    Regarding files in /proc, /sys, /dev:




    • These filesystems are virtual FS (tmpfs) i.e. they reside on memory, not on disk


    • If you plan to rely on /proc, use /proc/1/ i.e. rely on something under PID 1, not any later PIDs to have reliability/consistency as the later PIDs (processes) are not guranteed to exist.








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 3 mins ago

























    answered 31 mins ago









    heemaylheemayl

    35.6k376105




    35.6k376105













    • Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)

      – Crouching Kitten
      28 mins ago













    • Thanks. With find / -type d -perm 0400 -user root I have found the directory /proc/20/map_files/, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd, then it always fails. Does that folder always exist on Ubuntu?

      – Crouching Kitten
      15 mins ago











    • @CrouchingKitten, the directories in /proc/1/ might be safer, since init always exists. But that's proc, not a regular filesystem, in case it matters.

      – ilkkachu
      9 mins ago











    • Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that /proc/1/fdinfo/0 works on modern Ubuntus.

      – Crouching Kitten
      6 mins ago





















    • Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)

      – Crouching Kitten
      28 mins ago













    • Thanks. With find / -type d -perm 0400 -user root I have found the directory /proc/20/map_files/, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd, then it always fails. Does that folder always exist on Ubuntu?

      – Crouching Kitten
      15 mins ago











    • @CrouchingKitten, the directories in /proc/1/ might be safer, since init always exists. But that's proc, not a regular filesystem, in case it matters.

      – ilkkachu
      9 mins ago











    • Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that /proc/1/fdinfo/0 works on modern Ubuntus.

      – Crouching Kitten
      6 mins ago



















    Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)

    – Crouching Kitten
    28 mins ago







    Thanks, I think my question is wrong. I can still lstat files without read access to them. Maybe the access to the folder has to be limited? (I modified the title)

    – Crouching Kitten
    28 mins ago















    Thanks. With find / -type d -perm 0400 -user root I have found the directory /proc/20/map_files/, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd, then it always fails. Does that folder always exist on Ubuntu?

    – Crouching Kitten
    15 mins ago





    Thanks. With find / -type d -perm 0400 -user root I have found the directory /proc/20/map_files/, if I refer to a made-up file name inside that folder, like /proc/20/map_files/asdasd, then it always fails. Does that folder always exist on Ubuntu?

    – Crouching Kitten
    15 mins ago













    @CrouchingKitten, the directories in /proc/1/ might be safer, since init always exists. But that's proc, not a regular filesystem, in case it matters.

    – ilkkachu
    9 mins ago





    @CrouchingKitten, the directories in /proc/1/ might be safer, since init always exists. But that's proc, not a regular filesystem, in case it matters.

    – ilkkachu
    9 mins ago













    Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that /proc/1/fdinfo/0 works on modern Ubuntus.

    – Crouching Kitten
    6 mins ago







    Thanks I gave an upvote, but accepted the other answer, because he said it is guaranteed that /proc/1/fdinfo/0 works on modern Ubuntus.

    – Crouching Kitten
    6 mins ago













    1














    Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)



    The most obvious one is:




    EACCES
    Search permission is denied for one of the directories in the path prefix of path.




    So you need a directory you can't read from.



    Yes, you can look for one that's already in your system (perhaps /var/lib/private if it exists?) But you might as well create one yourself, with the equivalent of:



    $ mkdir myprivatedir
    $ touch myprivatedir/myunreachablefile
    $ chmod 0 myprivatedir
    $ ls -l myprivatedir/myunreachablefile


    The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)



    There's another creative way to make lstat(2) fail, looking at its man page:




    ENOTDIR
    A component of the path prefix of path is not a directory.




    So, trying to access a file such as /etc/passwd/nonexistent should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.



    Another one is:




    ENAMETOOLONG
    path is too long.




    But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)



    Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e or the equivalent [ -e ...] from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.





    share




























      1














      Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)



      The most obvious one is:




      EACCES
      Search permission is denied for one of the directories in the path prefix of path.




      So you need a directory you can't read from.



      Yes, you can look for one that's already in your system (perhaps /var/lib/private if it exists?) But you might as well create one yourself, with the equivalent of:



      $ mkdir myprivatedir
      $ touch myprivatedir/myunreachablefile
      $ chmod 0 myprivatedir
      $ ls -l myprivatedir/myunreachablefile


      The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)



      There's another creative way to make lstat(2) fail, looking at its man page:




      ENOTDIR
      A component of the path prefix of path is not a directory.




      So, trying to access a file such as /etc/passwd/nonexistent should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.



      Another one is:




      ENAMETOOLONG
      path is too long.




      But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)



      Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e or the equivalent [ -e ...] from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.





      share


























        1












        1








        1







        Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)



        The most obvious one is:




        EACCES
        Search permission is denied for one of the directories in the path prefix of path.




        So you need a directory you can't read from.



        Yes, you can look for one that's already in your system (perhaps /var/lib/private if it exists?) But you might as well create one yourself, with the equivalent of:



        $ mkdir myprivatedir
        $ touch myprivatedir/myunreachablefile
        $ chmod 0 myprivatedir
        $ ls -l myprivatedir/myunreachablefile


        The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)



        There's another creative way to make lstat(2) fail, looking at its man page:




        ENOTDIR
        A component of the path prefix of path is not a directory.




        So, trying to access a file such as /etc/passwd/nonexistent should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.



        Another one is:




        ENAMETOOLONG
        path is too long.




        But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)



        Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e or the equivalent [ -e ...] from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.





        share













        Looking at the lstat(2) man page you can get some inspiration on cases that might make it fail with errors other than ENOENT (file does not exist.)



        The most obvious one is:




        EACCES
        Search permission is denied for one of the directories in the path prefix of path.




        So you need a directory you can't read from.



        Yes, you can look for one that's already in your system (perhaps /var/lib/private if it exists?) But you might as well create one yourself, with the equivalent of:



        $ mkdir myprivatedir
        $ touch myprivatedir/myunreachablefile
        $ chmod 0 myprivatedir
        $ ls -l myprivatedir/myunreachablefile


        The lstat(2) operation will fail with EACCES here. (Removing all permissions from the directory ensures that. Maybe you don't even need that much and chmod -x removing execute permissions would be enough, since execute permissions on a directory are needed to access files under it.)



        There's another creative way to make lstat(2) fail, looking at its man page:




        ENOTDIR
        A component of the path prefix of path is not a directory.




        So, trying to access a file such as /etc/passwd/nonexistent should trigger this error, which again is different from ENOENT ("No such file or directory") and might suit your needs.



        Another one is:




        ENAMETOOLONG
        path is too long.




        But you might need a really long name for this one (I believe 4,096 bytes is the typical limit, but your system/filesystem might have a longer one.)



        Finally, it's hard to tell whether any of these will be actually useful for you. You say you want something that doesn't trigger the "file doesn't exist" scenario. While typically that means an ENOENT error, in practice many higher-level checks will simply interpret any errors from lstat(2) as "does not exist". For example test -e or the equivalent [ -e ...] from the shell might simply just interpret all of the above as "does not exist", especially since it doesn't have a good way to return a different error message and not returning an error would imply the file exists, which is most certainly not the case.






        share











        share


        share










        answered 4 mins ago









        filbrandenfilbranden

        9,21621342




        9,21621342






























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