Symbolic Multivariate DistributionPrevent Part[] from trying to extract parts of symbolic expressionsHow do...

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Symbolic Multivariate Distribution


Prevent Part[] from trying to extract parts of symbolic expressionsHow do you pattern match a DataDistributionIs it possible to create a compiled function with some symbolic arguments?Reverse engineer a sample value from a CDFInconsistent DistributionFitTest results?Pattern matching with PDF, Distributed and multivariate distributionsGiven an exact formula, how can Mathematica find a probability distribution whose PDF matches it?TransformedDistribution using integration with parameter doesn't workPDF of sum of squared UniformDistribution (TransformedDistribution)How do I check and justifiy a symbolic result returned by Mathematica?













2












$begingroup$


If I try to input a symbolic multivariate distribution, I do not get a useful result.



PDF[MultinormalDistribution[m, S], x]

(* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers. *)

(* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers.*)
(* PDF[MultinormalDistribution[m, S], x] *)


Clearly, Mathematica could return an appropriate symbolic expression. Is there any way of making it do so?










share|improve this question









$endgroup$

















    2












    $begingroup$


    If I try to input a symbolic multivariate distribution, I do not get a useful result.



    PDF[MultinormalDistribution[m, S], x]

    (* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers. *)

    (* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers.*)
    (* PDF[MultinormalDistribution[m, S], x] *)


    Clearly, Mathematica could return an appropriate symbolic expression. Is there any way of making it do so?










    share|improve this question









    $endgroup$















      2












      2








      2





      $begingroup$


      If I try to input a symbolic multivariate distribution, I do not get a useful result.



      PDF[MultinormalDistribution[m, S], x]

      (* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers. *)

      (* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers.*)
      (* PDF[MultinormalDistribution[m, S], x] *)


      Clearly, Mathematica could return an appropriate symbolic expression. Is there any way of making it do so?










      share|improve this question









      $endgroup$




      If I try to input a symbolic multivariate distribution, I do not get a useful result.



      PDF[MultinormalDistribution[m, S], x]

      (* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers. *)

      (* During evaluation of MultinormalDistribution::vrprm: The value m at position 1 in MultinormalDistribution[m,S] is expected to be a list of real numbers.*)
      (* PDF[MultinormalDistribution[m, S], x] *)


      Clearly, Mathematica could return an appropriate symbolic expression. Is there any way of making it do so?







      probability-or-statistics symbolic






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 hours ago









      mikadomikado

      6,9371929




      6,9371929






















          1 Answer
          1






          active

          oldest

          votes


















          5












          $begingroup$

          You need to supply Mathematica with the structure of your variables:



          (* dimension of distribution *)
          n = 2;

          PDF[
          MultinormalDistribution[
          Array[Subscript[m, ##] &, n],
          Array[Subscript[S, Sequence @@ Sort@{##}] &, {n, n}]
          ],
          Array[Subscript[x, ##] &, n]
          ]


          enter image description here
          We use Array to construct variables of the form Subscript[var,i,j,…] (you can of course use any other form that is more convenient). Note that S is explicitly made symmetric by sorting the indices. The code works without this, but this way there are no "fake" parameters.



          Note: As pointed out by @BobHanlon in the comments, Subscript can often cause issues if used blindly. For actual use, it is much safer to simply use indexed variables such as Array[x, n].






          share|improve this answer











          $endgroup$













          • $begingroup$
            Rather than using subscripted variables, I recommend using indexed variables and then using Format to display the indexed variables as subscripted variables. Subscripted variables tend to cause problems in solvers.
            $endgroup$
            – Bob Hanlon
            28 mins ago










          • $begingroup$
            I am aware of that - I just thought that for a quick demonstration, it would be good enough and it's easy to read. But I will add a comment to the answer to point out potential issues.
            $endgroup$
            – Lukas Lang
            25 mins ago












          Your Answer








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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          5












          $begingroup$

          You need to supply Mathematica with the structure of your variables:



          (* dimension of distribution *)
          n = 2;

          PDF[
          MultinormalDistribution[
          Array[Subscript[m, ##] &, n],
          Array[Subscript[S, Sequence @@ Sort@{##}] &, {n, n}]
          ],
          Array[Subscript[x, ##] &, n]
          ]


          enter image description here
          We use Array to construct variables of the form Subscript[var,i,j,…] (you can of course use any other form that is more convenient). Note that S is explicitly made symmetric by sorting the indices. The code works without this, but this way there are no "fake" parameters.



          Note: As pointed out by @BobHanlon in the comments, Subscript can often cause issues if used blindly. For actual use, it is much safer to simply use indexed variables such as Array[x, n].






          share|improve this answer











          $endgroup$













          • $begingroup$
            Rather than using subscripted variables, I recommend using indexed variables and then using Format to display the indexed variables as subscripted variables. Subscripted variables tend to cause problems in solvers.
            $endgroup$
            – Bob Hanlon
            28 mins ago










          • $begingroup$
            I am aware of that - I just thought that for a quick demonstration, it would be good enough and it's easy to read. But I will add a comment to the answer to point out potential issues.
            $endgroup$
            – Lukas Lang
            25 mins ago
















          5












          $begingroup$

          You need to supply Mathematica with the structure of your variables:



          (* dimension of distribution *)
          n = 2;

          PDF[
          MultinormalDistribution[
          Array[Subscript[m, ##] &, n],
          Array[Subscript[S, Sequence @@ Sort@{##}] &, {n, n}]
          ],
          Array[Subscript[x, ##] &, n]
          ]


          enter image description here
          We use Array to construct variables of the form Subscript[var,i,j,…] (you can of course use any other form that is more convenient). Note that S is explicitly made symmetric by sorting the indices. The code works without this, but this way there are no "fake" parameters.



          Note: As pointed out by @BobHanlon in the comments, Subscript can often cause issues if used blindly. For actual use, it is much safer to simply use indexed variables such as Array[x, n].






          share|improve this answer











          $endgroup$













          • $begingroup$
            Rather than using subscripted variables, I recommend using indexed variables and then using Format to display the indexed variables as subscripted variables. Subscripted variables tend to cause problems in solvers.
            $endgroup$
            – Bob Hanlon
            28 mins ago










          • $begingroup$
            I am aware of that - I just thought that for a quick demonstration, it would be good enough and it's easy to read. But I will add a comment to the answer to point out potential issues.
            $endgroup$
            – Lukas Lang
            25 mins ago














          5












          5








          5





          $begingroup$

          You need to supply Mathematica with the structure of your variables:



          (* dimension of distribution *)
          n = 2;

          PDF[
          MultinormalDistribution[
          Array[Subscript[m, ##] &, n],
          Array[Subscript[S, Sequence @@ Sort@{##}] &, {n, n}]
          ],
          Array[Subscript[x, ##] &, n]
          ]


          enter image description here
          We use Array to construct variables of the form Subscript[var,i,j,…] (you can of course use any other form that is more convenient). Note that S is explicitly made symmetric by sorting the indices. The code works without this, but this way there are no "fake" parameters.



          Note: As pointed out by @BobHanlon in the comments, Subscript can often cause issues if used blindly. For actual use, it is much safer to simply use indexed variables such as Array[x, n].






          share|improve this answer











          $endgroup$



          You need to supply Mathematica with the structure of your variables:



          (* dimension of distribution *)
          n = 2;

          PDF[
          MultinormalDistribution[
          Array[Subscript[m, ##] &, n],
          Array[Subscript[S, Sequence @@ Sort@{##}] &, {n, n}]
          ],
          Array[Subscript[x, ##] &, n]
          ]


          enter image description here
          We use Array to construct variables of the form Subscript[var,i,j,…] (you can of course use any other form that is more convenient). Note that S is explicitly made symmetric by sorting the indices. The code works without this, but this way there are no "fake" parameters.



          Note: As pointed out by @BobHanlon in the comments, Subscript can often cause issues if used blindly. For actual use, it is much safer to simply use indexed variables such as Array[x, n].







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 20 mins ago

























          answered 2 hours ago









          Lukas LangLukas Lang

          7,44011032




          7,44011032












          • $begingroup$
            Rather than using subscripted variables, I recommend using indexed variables and then using Format to display the indexed variables as subscripted variables. Subscripted variables tend to cause problems in solvers.
            $endgroup$
            – Bob Hanlon
            28 mins ago










          • $begingroup$
            I am aware of that - I just thought that for a quick demonstration, it would be good enough and it's easy to read. But I will add a comment to the answer to point out potential issues.
            $endgroup$
            – Lukas Lang
            25 mins ago


















          • $begingroup$
            Rather than using subscripted variables, I recommend using indexed variables and then using Format to display the indexed variables as subscripted variables. Subscripted variables tend to cause problems in solvers.
            $endgroup$
            – Bob Hanlon
            28 mins ago










          • $begingroup$
            I am aware of that - I just thought that for a quick demonstration, it would be good enough and it's easy to read. But I will add a comment to the answer to point out potential issues.
            $endgroup$
            – Lukas Lang
            25 mins ago
















          $begingroup$
          Rather than using subscripted variables, I recommend using indexed variables and then using Format to display the indexed variables as subscripted variables. Subscripted variables tend to cause problems in solvers.
          $endgroup$
          – Bob Hanlon
          28 mins ago




          $begingroup$
          Rather than using subscripted variables, I recommend using indexed variables and then using Format to display the indexed variables as subscripted variables. Subscripted variables tend to cause problems in solvers.
          $endgroup$
          – Bob Hanlon
          28 mins ago












          $begingroup$
          I am aware of that - I just thought that for a quick demonstration, it would be good enough and it's easy to read. But I will add a comment to the answer to point out potential issues.
          $endgroup$
          – Lukas Lang
          25 mins ago




          $begingroup$
          I am aware of that - I just thought that for a quick demonstration, it would be good enough and it's easy to read. But I will add a comment to the answer to point out potential issues.
          $endgroup$
          – Lukas Lang
          25 mins ago


















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