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using NDEigensystem to solve the Mathieu equation
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using NDEigensystem to solve the Mathieu equation
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$begingroup$
To be able to apply the differentialequation capabilities of Mathematica to my graduate thesis, I am trying to apply NDEigensystem to an eigenproblem whose solution I know, but I am having some trouble doing so.
As a test problem, I am using an algebraic version of the Mathieu equation,
$$(1-zeta^{2})w^{primeprime}-zeta w^{prime}+left(a+2q-4qzeta^{2}right)w=0$$
For this example I set $q=4/3$ and take only the first three eigenpairs:
m = 3; q = 4/3;
op = -(1 - ζ^2) u''[ζ] + ζ u'[ζ] + 2 q (2 ζ^2 - 1) u[ζ];
bc = DirichletCondition[u[ζ] == 0, True];
{λ, fl} = NDEigensystem[{op, bc}, u, {ζ, 0, 1}, m];
I chose the Mathieu equation as a nontrivial example as Mathematica already has a function for it's evaluation:
λt = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
The problem is, I do not get the expected eigenvalues!
λ
(* {4.0708, 17.3259, 39.1877} *)
N[λt]
(* {3.85298, 16.0581, 36.0254} *)
And of course, plotting shows that the eigenequation is not satisfied at all:
With[{u = fl[[1]], b = λ[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
With[{u = flt[[1]], b = λt[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
What was wrong with my attempt? If I can get this example to work, I should be able to apply it to my actual, more complicated problem, so any Good Ideas would be welcome.
differential-equations finite-element-method
New contributor
$endgroup$
add a comment |
$begingroup$
To be able to apply the differentialequation capabilities of Mathematica to my graduate thesis, I am trying to apply NDEigensystem to an eigenproblem whose solution I know, but I am having some trouble doing so.
As a test problem, I am using an algebraic version of the Mathieu equation,
$$(1-zeta^{2})w^{primeprime}-zeta w^{prime}+left(a+2q-4qzeta^{2}right)w=0$$
For this example I set $q=4/3$ and take only the first three eigenpairs:
m = 3; q = 4/3;
op = -(1 - ζ^2) u''[ζ] + ζ u'[ζ] + 2 q (2 ζ^2 - 1) u[ζ];
bc = DirichletCondition[u[ζ] == 0, True];
{λ, fl} = NDEigensystem[{op, bc}, u, {ζ, 0, 1}, m];
I chose the Mathieu equation as a nontrivial example as Mathematica already has a function for it's evaluation:
λt = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
The problem is, I do not get the expected eigenvalues!
λ
(* {4.0708, 17.3259, 39.1877} *)
N[λt]
(* {3.85298, 16.0581, 36.0254} *)
And of course, plotting shows that the eigenequation is not satisfied at all:
With[{u = fl[[1]], b = λ[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
With[{u = flt[[1]], b = λt[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
What was wrong with my attempt? If I can get this example to work, I should be able to apply it to my actual, more complicated problem, so any Good Ideas would be welcome.
differential-equations finite-element-method
New contributor
$endgroup$
add a comment |
$begingroup$
To be able to apply the differentialequation capabilities of Mathematica to my graduate thesis, I am trying to apply NDEigensystem to an eigenproblem whose solution I know, but I am having some trouble doing so.
As a test problem, I am using an algebraic version of the Mathieu equation,
$$(1-zeta^{2})w^{primeprime}-zeta w^{prime}+left(a+2q-4qzeta^{2}right)w=0$$
For this example I set $q=4/3$ and take only the first three eigenpairs:
m = 3; q = 4/3;
op = -(1 - ζ^2) u''[ζ] + ζ u'[ζ] + 2 q (2 ζ^2 - 1) u[ζ];
bc = DirichletCondition[u[ζ] == 0, True];
{λ, fl} = NDEigensystem[{op, bc}, u, {ζ, 0, 1}, m];
I chose the Mathieu equation as a nontrivial example as Mathematica already has a function for it's evaluation:
λt = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
The problem is, I do not get the expected eigenvalues!
λ
(* {4.0708, 17.3259, 39.1877} *)
N[λt]
(* {3.85298, 16.0581, 36.0254} *)
And of course, plotting shows that the eigenequation is not satisfied at all:
With[{u = fl[[1]], b = λ[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
With[{u = flt[[1]], b = λt[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
What was wrong with my attempt? If I can get this example to work, I should be able to apply it to my actual, more complicated problem, so any Good Ideas would be welcome.
differential-equations finite-element-method
New contributor
$endgroup$
To be able to apply the differentialequation capabilities of Mathematica to my graduate thesis, I am trying to apply NDEigensystem to an eigenproblem whose solution I know, but I am having some trouble doing so.
As a test problem, I am using an algebraic version of the Mathieu equation,
$$(1-zeta^{2})w^{primeprime}-zeta w^{prime}+left(a+2q-4qzeta^{2}right)w=0$$
For this example I set $q=4/3$ and take only the first three eigenpairs:
m = 3; q = 4/3;
op = -(1 - ζ^2) u''[ζ] + ζ u'[ζ] + 2 q (2 ζ^2 - 1) u[ζ];
bc = DirichletCondition[u[ζ] == 0, True];
{λ, fl} = NDEigensystem[{op, bc}, u, {ζ, 0, 1}, m];
I chose the Mathieu equation as a nontrivial example as Mathematica already has a function for it's evaluation:
λt = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
The problem is, I do not get the expected eigenvalues!
λ
(* {4.0708, 17.3259, 39.1877} *)
N[λt]
(* {3.85298, 16.0581, 36.0254} *)
And of course, plotting shows that the eigenequation is not satisfied at all:
With[{u = fl[[1]], b = λ[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
With[{u = flt[[1]], b = λt[[1]]},
Plot[(1 - ζ^2) u''[ζ] - ζ u'[ζ] + (b + 2 q - 4 q ζ^2) u[ζ], {ζ, 0, 1}]]
What was wrong with my attempt? If I can get this example to work, I should be able to apply it to my actual, more complicated problem, so any Good Ideas would be welcome.
differential-equations finite-element-method
differential-equations finite-element-method
New contributor
New contributor
edited 1 hour ago
user21
21k55998
21k55998
New contributor
asked 3 hours ago
宮川園子宮川園子
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2 Answers
2
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oldest
votes
$begingroup$
It looks to me like NDEigensystem
is struggling with the singularity at $zeta=1$, as does the method that I'm going to show. But perhaps it'll be useful for you, at least as a cross-check.
I have a package for numerically calculating solutions of eigenvalue problems using the Evans function via the method of compound matrices, which is hosted on github. See my answers to other questions, the example notebook on the github or this introduction for some more details.
First we install the package (only need to do this the first time):
Needs["PacletManager`"]
PacletInstall["CompoundMatrixMethod",
"Site" -> "http://raw.githubusercontent.com/paclets/Repository/master"]
Then we first need to turn the ODEs into a matrix form $mathbf{y}'=mathbf{A} cdot mathbf{y}$, using my function ToMatrixSystem
:
Needs["CompoundMatrixMethod`"]
sys[ζend_] = ToMatrixSystem[op == a u[ζ], {u[0] == 0, u[ζend] == 0}, u, {ζ, 0, ζend}, a]
Now the function Evans will calculate the Evans function (also known as the Miss-Distance function) for any given value of $a$ and $zeta_{end}$; this is an analytic function whose roots coincide with eigenvalues of the original equation.
Plugging in $zeta_{end} = 1$ fails due to the singularity, but you can try moving the endpoint slightly away:
FindRoot[Evans[a, sys[1 - 10^-3]], {a, 3}]
(* {a -> 4.00335} *)
Moving the endpoint closer approaches the correct value, but I can't get the exact value with this method.
FindRoot[Evans[a, sys[1 - 10^-10], WorkingPrecision -> 30], {a, 3},
WorkingPrecision -> 30] // Quiet
(* {a -> 3.85301} *)
You can see the same effect for the other roots.
$endgroup$
add a comment |
$begingroup$
If you refine the mesh, you will get closer:
m = 3; q = 4/3;
op = -(1 - [Zeta]^2) u''[[Zeta]] + [Zeta] u'[[Zeta]] +
2 q (2 [Zeta]^2 - 1) u[[Zeta]];
bc = DirichletCondition[u[[Zeta]] == 0, True];
{[Lambda], fl} =
NDEigensystem[{op, bc}, u, {[Zeta], 0, 1}, m,
Method -> {"PDEDiscretization" -> {"FiniteElement", {"MeshOptions"
-> {"MaxCellMeasure" -> 0.00001}}}}];
[Lambda]
{3.855, 16.074, 36.064}
[Lambda]t = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[
With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
[Lambda]t // N
{3.852, 16.058, 36.025}
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
It looks to me like NDEigensystem
is struggling with the singularity at $zeta=1$, as does the method that I'm going to show. But perhaps it'll be useful for you, at least as a cross-check.
I have a package for numerically calculating solutions of eigenvalue problems using the Evans function via the method of compound matrices, which is hosted on github. See my answers to other questions, the example notebook on the github or this introduction for some more details.
First we install the package (only need to do this the first time):
Needs["PacletManager`"]
PacletInstall["CompoundMatrixMethod",
"Site" -> "http://raw.githubusercontent.com/paclets/Repository/master"]
Then we first need to turn the ODEs into a matrix form $mathbf{y}'=mathbf{A} cdot mathbf{y}$, using my function ToMatrixSystem
:
Needs["CompoundMatrixMethod`"]
sys[ζend_] = ToMatrixSystem[op == a u[ζ], {u[0] == 0, u[ζend] == 0}, u, {ζ, 0, ζend}, a]
Now the function Evans will calculate the Evans function (also known as the Miss-Distance function) for any given value of $a$ and $zeta_{end}$; this is an analytic function whose roots coincide with eigenvalues of the original equation.
Plugging in $zeta_{end} = 1$ fails due to the singularity, but you can try moving the endpoint slightly away:
FindRoot[Evans[a, sys[1 - 10^-3]], {a, 3}]
(* {a -> 4.00335} *)
Moving the endpoint closer approaches the correct value, but I can't get the exact value with this method.
FindRoot[Evans[a, sys[1 - 10^-10], WorkingPrecision -> 30], {a, 3},
WorkingPrecision -> 30] // Quiet
(* {a -> 3.85301} *)
You can see the same effect for the other roots.
$endgroup$
add a comment |
$begingroup$
It looks to me like NDEigensystem
is struggling with the singularity at $zeta=1$, as does the method that I'm going to show. But perhaps it'll be useful for you, at least as a cross-check.
I have a package for numerically calculating solutions of eigenvalue problems using the Evans function via the method of compound matrices, which is hosted on github. See my answers to other questions, the example notebook on the github or this introduction for some more details.
First we install the package (only need to do this the first time):
Needs["PacletManager`"]
PacletInstall["CompoundMatrixMethod",
"Site" -> "http://raw.githubusercontent.com/paclets/Repository/master"]
Then we first need to turn the ODEs into a matrix form $mathbf{y}'=mathbf{A} cdot mathbf{y}$, using my function ToMatrixSystem
:
Needs["CompoundMatrixMethod`"]
sys[ζend_] = ToMatrixSystem[op == a u[ζ], {u[0] == 0, u[ζend] == 0}, u, {ζ, 0, ζend}, a]
Now the function Evans will calculate the Evans function (also known as the Miss-Distance function) for any given value of $a$ and $zeta_{end}$; this is an analytic function whose roots coincide with eigenvalues of the original equation.
Plugging in $zeta_{end} = 1$ fails due to the singularity, but you can try moving the endpoint slightly away:
FindRoot[Evans[a, sys[1 - 10^-3]], {a, 3}]
(* {a -> 4.00335} *)
Moving the endpoint closer approaches the correct value, but I can't get the exact value with this method.
FindRoot[Evans[a, sys[1 - 10^-10], WorkingPrecision -> 30], {a, 3},
WorkingPrecision -> 30] // Quiet
(* {a -> 3.85301} *)
You can see the same effect for the other roots.
$endgroup$
add a comment |
$begingroup$
It looks to me like NDEigensystem
is struggling with the singularity at $zeta=1$, as does the method that I'm going to show. But perhaps it'll be useful for you, at least as a cross-check.
I have a package for numerically calculating solutions of eigenvalue problems using the Evans function via the method of compound matrices, which is hosted on github. See my answers to other questions, the example notebook on the github or this introduction for some more details.
First we install the package (only need to do this the first time):
Needs["PacletManager`"]
PacletInstall["CompoundMatrixMethod",
"Site" -> "http://raw.githubusercontent.com/paclets/Repository/master"]
Then we first need to turn the ODEs into a matrix form $mathbf{y}'=mathbf{A} cdot mathbf{y}$, using my function ToMatrixSystem
:
Needs["CompoundMatrixMethod`"]
sys[ζend_] = ToMatrixSystem[op == a u[ζ], {u[0] == 0, u[ζend] == 0}, u, {ζ, 0, ζend}, a]
Now the function Evans will calculate the Evans function (also known as the Miss-Distance function) for any given value of $a$ and $zeta_{end}$; this is an analytic function whose roots coincide with eigenvalues of the original equation.
Plugging in $zeta_{end} = 1$ fails due to the singularity, but you can try moving the endpoint slightly away:
FindRoot[Evans[a, sys[1 - 10^-3]], {a, 3}]
(* {a -> 4.00335} *)
Moving the endpoint closer approaches the correct value, but I can't get the exact value with this method.
FindRoot[Evans[a, sys[1 - 10^-10], WorkingPrecision -> 30], {a, 3},
WorkingPrecision -> 30] // Quiet
(* {a -> 3.85301} *)
You can see the same effect for the other roots.
$endgroup$
It looks to me like NDEigensystem
is struggling with the singularity at $zeta=1$, as does the method that I'm going to show. But perhaps it'll be useful for you, at least as a cross-check.
I have a package for numerically calculating solutions of eigenvalue problems using the Evans function via the method of compound matrices, which is hosted on github. See my answers to other questions, the example notebook on the github or this introduction for some more details.
First we install the package (only need to do this the first time):
Needs["PacletManager`"]
PacletInstall["CompoundMatrixMethod",
"Site" -> "http://raw.githubusercontent.com/paclets/Repository/master"]
Then we first need to turn the ODEs into a matrix form $mathbf{y}'=mathbf{A} cdot mathbf{y}$, using my function ToMatrixSystem
:
Needs["CompoundMatrixMethod`"]
sys[ζend_] = ToMatrixSystem[op == a u[ζ], {u[0] == 0, u[ζend] == 0}, u, {ζ, 0, ζend}, a]
Now the function Evans will calculate the Evans function (also known as the Miss-Distance function) for any given value of $a$ and $zeta_{end}$; this is an analytic function whose roots coincide with eigenvalues of the original equation.
Plugging in $zeta_{end} = 1$ fails due to the singularity, but you can try moving the endpoint slightly away:
FindRoot[Evans[a, sys[1 - 10^-3]], {a, 3}]
(* {a -> 4.00335} *)
Moving the endpoint closer approaches the correct value, but I can't get the exact value with this method.
FindRoot[Evans[a, sys[1 - 10^-10], WorkingPrecision -> 30], {a, 3},
WorkingPrecision -> 30] // Quiet
(* {a -> 3.85301} *)
You can see the same effect for the other roots.
answered 1 hour ago
KraZugKraZug
3,53821130
3,53821130
add a comment |
add a comment |
$begingroup$
If you refine the mesh, you will get closer:
m = 3; q = 4/3;
op = -(1 - [Zeta]^2) u''[[Zeta]] + [Zeta] u'[[Zeta]] +
2 q (2 [Zeta]^2 - 1) u[[Zeta]];
bc = DirichletCondition[u[[Zeta]] == 0, True];
{[Lambda], fl} =
NDEigensystem[{op, bc}, u, {[Zeta], 0, 1}, m,
Method -> {"PDEDiscretization" -> {"FiniteElement", {"MeshOptions"
-> {"MaxCellMeasure" -> 0.00001}}}}];
[Lambda]
{3.855, 16.074, 36.064}
[Lambda]t = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[
With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
[Lambda]t // N
{3.852, 16.058, 36.025}
$endgroup$
add a comment |
$begingroup$
If you refine the mesh, you will get closer:
m = 3; q = 4/3;
op = -(1 - [Zeta]^2) u''[[Zeta]] + [Zeta] u'[[Zeta]] +
2 q (2 [Zeta]^2 - 1) u[[Zeta]];
bc = DirichletCondition[u[[Zeta]] == 0, True];
{[Lambda], fl} =
NDEigensystem[{op, bc}, u, {[Zeta], 0, 1}, m,
Method -> {"PDEDiscretization" -> {"FiniteElement", {"MeshOptions"
-> {"MaxCellMeasure" -> 0.00001}}}}];
[Lambda]
{3.855, 16.074, 36.064}
[Lambda]t = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[
With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
[Lambda]t // N
{3.852, 16.058, 36.025}
$endgroup$
add a comment |
$begingroup$
If you refine the mesh, you will get closer:
m = 3; q = 4/3;
op = -(1 - [Zeta]^2) u''[[Zeta]] + [Zeta] u'[[Zeta]] +
2 q (2 [Zeta]^2 - 1) u[[Zeta]];
bc = DirichletCondition[u[[Zeta]] == 0, True];
{[Lambda], fl} =
NDEigensystem[{op, bc}, u, {[Zeta], 0, 1}, m,
Method -> {"PDEDiscretization" -> {"FiniteElement", {"MeshOptions"
-> {"MaxCellMeasure" -> 0.00001}}}}];
[Lambda]
{3.855, 16.074, 36.064}
[Lambda]t = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[
With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
[Lambda]t // N
{3.852, 16.058, 36.025}
$endgroup$
If you refine the mesh, you will get closer:
m = 3; q = 4/3;
op = -(1 - [Zeta]^2) u''[[Zeta]] + [Zeta] u'[[Zeta]] +
2 q (2 [Zeta]^2 - 1) u[[Zeta]];
bc = DirichletCondition[u[[Zeta]] == 0, True];
{[Lambda], fl} =
NDEigensystem[{op, bc}, u, {[Zeta], 0, 1}, m,
Method -> {"PDEDiscretization" -> {"FiniteElement", {"MeshOptions"
-> {"MaxCellMeasure" -> 0.00001}}}}];
[Lambda]
{3.855, 16.074, 36.064}
[Lambda]t = Table[MathieuCharacteristicB[2 k, q], {k, m}];
flt = Table[
With[{j = j},
MathieuS[MathieuCharacteristicB[2 k, q], q, ArcCos[#]] &], {k, m}];
[Lambda]t // N
{3.852, 16.058, 36.025}
answered 1 hour ago
user21user21
21k55998
21k55998
add a comment |
add a comment |
宮川園子 is a new contributor. Be nice, and check out our Code of Conduct.
宮川園子 is a new contributor. Be nice, and check out our Code of Conduct.
宮川園子 is a new contributor. Be nice, and check out our Code of Conduct.
宮川園子 is a new contributor. Be nice, and check out our Code of Conduct.
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