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How to copy the rest of lines of a file to another file

How to print all lines after a match up to the end of the file?compare two files get identical list“Ungrep” - which patterns aren't matchedOutputting common lines from 2 files and uncommon lines from both the files in one output fileReplace lines matching a pattern with lines from another file in orderCompare two files and print only the first word of the lines which don't match along with a stringgnuwin bash If .txt file contains string copy filecopy files and append in another directory?How do I create a new txt file from another file which is a list?counting the matched linesHow to grep the rows with same column in different files and print specific column and add onto the original file?

1

0

I have the string xyz which is a line in file1.txt, I want to copy all the lines after xyz in file1.txt to a new file file2.txt. How can I achieve this?

I know about cat command. But how to specify the starting line?

files grep cat file-copy file-transfer

share|improve this question

asked 1 hour ago

user9371654user9371654

30117

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Do you want to include that xyz line or exclude it from being copied ? Also, what happens if you have multiple lines matching xyz ?
  
  – don_crissti
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Possible duplicate of How to print all lines after a match up to the end of the file?
  
  – Kusalananda
  1 hour ago
  

  
  
  
  

add a comment | 

1

0

I have the string xyz which is a line in file1.txt, I want to copy all the lines after xyz in file1.txt to a new file file2.txt. How can I achieve this?

I know about cat command. But how to specify the starting line?

files grep cat file-copy file-transfer

share|improve this question

asked 1 hour ago

user9371654user9371654

30117

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Do you want to include that xyz line or exclude it from being copied ? Also, what happens if you have multiple lines matching xyz ?
  
  – don_crissti
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Possible duplicate of How to print all lines after a match up to the end of the file?
  
  – Kusalananda
  1 hour ago
  

  
  
  
  

add a comment | 

I have the string xyz which is a line in file1.txt, I want to copy all the lines after xyz in file1.txt to a new file file2.txt. How can I achieve this?

I know about cat command. But how to specify the starting line?

files grep cat file-copy file-transfer

share|improve this question

asked 1 hour ago

user9371654user9371654

30117

share|improve this question

asked 1 hour ago

user9371654user9371654

30117

share|improve this question

asked 1 hour ago

user9371654user9371654

30117

asked 1 hour ago

user9371654user9371654

30117

asked 1 hour ago

user9371654user9371654

30117

4 Answers
4

active

oldest

votes

2

Using GNU sed

To copy all lines after xyz, try:

sed '0,/xyz/d' file1.txt >file2.txt

1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.

Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)

Example

Consider this test file:

$ cat file1.txt

a

b

xyz

c

d

Run our command:

$ sed '1,/xyz/d' file1.txt >file2.txt

$ cat file2.txt

c

d

Using awk

The same logic can used with awk:

awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt

NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.

share|improve this answer

edited 55 mins ago

answered 1 hour ago

John1024John1024

47.5k5110125

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Thanks. Answer updated to include a GNU sed solution instead.
  
  – John1024
  55 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The proper way to do this (portably) with sed is shown in mikeserv's answer to the duplicate Q.
  
  – don_crissti
  52 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
  
  – John1024
  38 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @John1024 What sed are you using there?
  
  – Kusalananda
  32 secs ago
  

  
  
  
  

add a comment | 

1

With ed:

ed -s file.txt <<< $'/xyz/+1,$w file2.txt'

This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.

share|improve this answer

answered 25 mins ago

Jeff SchallerJeff Schaller

43.2k1159138

add a comment | 

0

$ sed -n '/xyz/,$p' file.txt > file2.txt

With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.

share|improve this answer

answered 1 hour ago

finswimmerfinswimmer

72917

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This would also print the line matching xyz, not from the line after.
  
  – Kusalananda
  1 hour ago
  

  
  
  
  

add a comment | 

0

There is also csplit :

csplit -s file1.txt %xyz%1

share|improve this answer

answered 35 mins ago

ctac_ctac_

1,4221210

add a comment | 

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2

Using GNU sed

To copy all lines after xyz, try:

sed '0,/xyz/d' file1.txt >file2.txt

1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.

Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)

Example

Consider this test file:

$ cat file1.txt

a

b

xyz

c

d

Run our command:

$ sed '1,/xyz/d' file1.txt >file2.txt

$ cat file2.txt

c

d

Using awk

The same logic can used with awk:

awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt

NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.

share|improve this answer

edited 55 mins ago

answered 1 hour ago

John1024John1024

47.5k5110125

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Thanks. Answer updated to include a GNU sed solution instead.
  
  – John1024
  55 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The proper way to do this (portably) with sed is shown in mikeserv's answer to the duplicate Q.
  
  – don_crissti
  52 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
  
  – John1024
  38 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @John1024 What sed are you using there?
  
  – Kusalananda
  32 secs ago
  

  
  
  
  

add a comment | 

2

Using GNU sed

To copy all lines after xyz, try:

sed '0,/xyz/d' file1.txt >file2.txt

1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.

Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)

Example

Consider this test file:

$ cat file1.txt

a

b

xyz

c

d

Run our command:

$ sed '1,/xyz/d' file1.txt >file2.txt

$ cat file2.txt

c

d

Using awk

The same logic can used with awk:

awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt

NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.

share|improve this answer

edited 55 mins ago

answered 1 hour ago

John1024John1024

47.5k5110125

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Thanks. Answer updated to include a GNU sed solution instead.
  
  – John1024
  55 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The proper way to do this (portably) with sed is shown in mikeserv's answer to the duplicate Q.
  
  – don_crissti
  52 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @don_crissti Are you referring to this answer? If so, it does not work for me. This is because sed, as currently written, like many other utilities, does not read in a line at a time; it reads in a buffer-full at a time.
  
  – John1024
  38 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @John1024 What sed are you using there?
  
  – Kusalananda
  32 secs ago
  

  
  
  
  

add a comment | 

Using GNU sed

To copy all lines after xyz, try:

sed '0,/xyz/d' file1.txt >file2.txt

1,/xyz/ specifies a range of lines starting with the first and ending with the first occurrence of a line matching xyz. d tells sed to delete those lines.

Note: For BSD/MacOS sed, one can use sed '1,/xyz/d' file1.txt >file2.txt but this only works if the first appearance of xyz is in the second line or later. (Hat tip: kusalananda.)

Example

Consider this test file:

$ cat file1.txt

a

b

xyz

c

d

Run our command:

$ sed '1,/xyz/d' file1.txt >file2.txt

$ cat file2.txt

c

d

Using awk

The same logic can used with awk:

awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt

NR==1,/xyz/{next} tells awk to skip over all lines from the first (NR==1) to the first line matching the regex xyz. 1 tells awk to print any remaining lines.

share|improve this answer

edited 55 mins ago

answered 1 hour ago

John1024John1024

47.5k5110125

sed '0,/xyz/d' file1.txt >file2.txt

$ cat file1.txt

a

b

xyz

c

d

$ sed '1,/xyz/d' file1.txt >file2.txt

$ cat file2.txt

c

d

awk 'NR==1,/xyz/{next} 1' file1.txt >file2.txt

share|improve this answer

edited 55 mins ago

answered 1 hour ago

John1024John1024

47.5k5110125

answered 1 hour ago

John1024John1024

47.5k5110125

answered 1 hour ago

John1024John1024

47.5k5110125

1

With ed:

ed -s file.txt <<< $'/xyz/+1,$w file2.txt'

This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.

share|improve this answer

answered 25 mins ago

Jeff SchallerJeff Schaller

43.2k1159138

add a comment | 

1

With ed:

ed -s file.txt <<< $'/xyz/+1,$w file2.txt'

This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.

share|improve this answer

answered 25 mins ago

Jeff SchallerJeff Schaller

43.2k1159138

add a comment | 

With ed:

ed -s file.txt <<< $'/xyz/+1,$w file2.txt'

This sends one (ranged) command to ed: from the line after (+1) the one containing xyz until the end of the file ($), write those lines to file2.txt.

share|improve this answer

answered 25 mins ago

Jeff SchallerJeff Schaller

43.2k1159138

ed -s file.txt <<< $'/xyz/+1,$w file2.txt'

share|improve this answer

answered 25 mins ago

Jeff SchallerJeff Schaller

43.2k1159138

answered 25 mins ago

Jeff SchallerJeff Schaller

43.2k1159138

answered 25 mins ago

Jeff SchallerJeff Schaller

43.2k1159138

0

$ sed -n '/xyz/,$p' file.txt > file2.txt

With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.

share|improve this answer

answered 1 hour ago

finswimmerfinswimmer

72917

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This would also print the line matching xyz, not from the line after.
  
  – Kusalananda
  1 hour ago
  

  
  
  
  

add a comment | 

0

$ sed -n '/xyz/,$p' file.txt > file2.txt

With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.

share|improve this answer

answered 1 hour ago

finswimmerfinswimmer

72917

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This would also print the line matching xyz, not from the line after.
  
  – Kusalananda
  1 hour ago
  

  
  
  
  

add a comment | 

$ sed -n '/xyz/,$p' file.txt > file2.txt

With -n we prevent sed to print every line. With $ means end of file end p stands for print line. So /xyz/$p means: If a line matches xyz print it until the end of the file.

share|improve this answer

answered 1 hour ago

finswimmerfinswimmer

72917

$ sed -n '/xyz/,$p' file.txt > file2.txt

share|improve this answer

answered 1 hour ago

finswimmerfinswimmer

72917

answered 1 hour ago

finswimmerfinswimmer

72917

answered 1 hour ago

finswimmerfinswimmer

72917

0

There is also csplit :

csplit -s file1.txt %xyz%1

share|improve this answer

answered 35 mins ago

ctac_ctac_

1,4221210

add a comment | 

0

There is also csplit :

csplit -s file1.txt %xyz%1

share|improve this answer

answered 35 mins ago

ctac_ctac_

1,4221210

add a comment | 

There is also csplit :

csplit -s file1.txt %xyz%1

share|improve this answer

answered 35 mins ago

ctac_ctac_

1,4221210

csplit -s file1.txt %xyz%1

share|improve this answer

answered 35 mins ago

ctac_ctac_

1,4221210

answered 35 mins ago

ctac_ctac_

1,4221210

answered 35 mins ago

ctac_ctac_

1,4221210