Solar incidence angle using google earth engine Planned maintenance scheduled April 17/18,...

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Solar incidence angle using google earth engine



Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
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I am using the formula for solar incidence angle : cosd = sin(a)sin(b) + cos(a)cos(b)cos(c), where a = 0.409sin((2pi/365)*DOY - 1.39), b = latitude of region and c = hour angle(taken as constant for daily estimates) the code for the formula is not working. My code:



// Zoom to a location.


Map.setCenter(80.34, 26.42); // Center on IIT Kanpur.
var G = 1367;



//dayofyear
var sequence = ee.Array(ee.List.sequence(1, 365));



//calculating the relative earth sun distance
var dr = sequence.multiply(2).divide(365).multiply(Math.PI).cos().multiply(0.033).add(1);
print(dr);



//calculating the solar incidence angle
//getting latitude and longitude of the geometry
var l8 = ee.ImageCollection("LANDSAT/LC08/C01/T1_SR")
.filterBounds(geometry);
var first = ee.Image(l8.first()).clip(geometry);

// get image projection
var proj = first.select([0]).projection();
// get coordinates image
var latlon = ee.Image.pixelLonLat().reproject(proj);
Map.addLayer(first, {bands:['B1'], min:0, max:500}, 'Image');



// put each lon lat in a list
var coords = latlon.select(['longitude', 'latitude'])
.reduceRegion({
reducer: ee.Reducer.toList(),
geometry: geometry,
scale: 30
});
var lat1 = ee.List(coords.get('latitude'));
var lat = ee.Array(lat1);
var lon = ee.List(coords.get('longitude'));
// zip them. Example: zip([1, 3],[2, 4]) --> [[1, 2], [3,4]]
var point_list = lon.zip(lat);
//getting the declination angle and hour angle
var d = ee.Number(dr).multiply(2*Math.PI).divide(365).subtract(1.39).sin().multiply(0.409);
var w = 1; //assuming average of hour angle as 0 degrees
var cosd1 = d.sin();
var cosd2 = lat.sin();
var cosd3 = d.cos();
var cosd4 = lat.cos();
var cosd01 = cosd1.multiply(cosd2);
//print(cosd01);
var cosd02 = cosd3.multiply(cosd4);
var cosd = cosd01.add(cosd02);









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    I am using the formula for solar incidence angle : cosd = sin(a)sin(b) + cos(a)cos(b)cos(c), where a = 0.409sin((2pi/365)*DOY - 1.39), b = latitude of region and c = hour angle(taken as constant for daily estimates) the code for the formula is not working. My code:



    // Zoom to a location.


    Map.setCenter(80.34, 26.42); // Center on IIT Kanpur.
    var G = 1367;



    //dayofyear
    var sequence = ee.Array(ee.List.sequence(1, 365));



    //calculating the relative earth sun distance
    var dr = sequence.multiply(2).divide(365).multiply(Math.PI).cos().multiply(0.033).add(1);
    print(dr);



    //calculating the solar incidence angle
    //getting latitude and longitude of the geometry
    var l8 = ee.ImageCollection("LANDSAT/LC08/C01/T1_SR")
    .filterBounds(geometry);
    var first = ee.Image(l8.first()).clip(geometry);

    // get image projection
    var proj = first.select([0]).projection();
    // get coordinates image
    var latlon = ee.Image.pixelLonLat().reproject(proj);
    Map.addLayer(first, {bands:['B1'], min:0, max:500}, 'Image');



    // put each lon lat in a list
    var coords = latlon.select(['longitude', 'latitude'])
    .reduceRegion({
    reducer: ee.Reducer.toList(),
    geometry: geometry,
    scale: 30
    });
    var lat1 = ee.List(coords.get('latitude'));
    var lat = ee.Array(lat1);
    var lon = ee.List(coords.get('longitude'));
    // zip them. Example: zip([1, 3],[2, 4]) --> [[1, 2], [3,4]]
    var point_list = lon.zip(lat);
    //getting the declination angle and hour angle
    var d = ee.Number(dr).multiply(2*Math.PI).divide(365).subtract(1.39).sin().multiply(0.409);
    var w = 1; //assuming average of hour angle as 0 degrees
    var cosd1 = d.sin();
    var cosd2 = lat.sin();
    var cosd3 = d.cos();
    var cosd4 = lat.cos();
    var cosd01 = cosd1.multiply(cosd2);
    //print(cosd01);
    var cosd02 = cosd3.multiply(cosd4);
    var cosd = cosd01.add(cosd02);









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      I am using the formula for solar incidence angle : cosd = sin(a)sin(b) + cos(a)cos(b)cos(c), where a = 0.409sin((2pi/365)*DOY - 1.39), b = latitude of region and c = hour angle(taken as constant for daily estimates) the code for the formula is not working. My code:



      // Zoom to a location.


      Map.setCenter(80.34, 26.42); // Center on IIT Kanpur.
      var G = 1367;



      //dayofyear
      var sequence = ee.Array(ee.List.sequence(1, 365));



      //calculating the relative earth sun distance
      var dr = sequence.multiply(2).divide(365).multiply(Math.PI).cos().multiply(0.033).add(1);
      print(dr);



      //calculating the solar incidence angle
      //getting latitude and longitude of the geometry
      var l8 = ee.ImageCollection("LANDSAT/LC08/C01/T1_SR")
      .filterBounds(geometry);
      var first = ee.Image(l8.first()).clip(geometry);

      // get image projection
      var proj = first.select([0]).projection();
      // get coordinates image
      var latlon = ee.Image.pixelLonLat().reproject(proj);
      Map.addLayer(first, {bands:['B1'], min:0, max:500}, 'Image');



      // put each lon lat in a list
      var coords = latlon.select(['longitude', 'latitude'])
      .reduceRegion({
      reducer: ee.Reducer.toList(),
      geometry: geometry,
      scale: 30
      });
      var lat1 = ee.List(coords.get('latitude'));
      var lat = ee.Array(lat1);
      var lon = ee.List(coords.get('longitude'));
      // zip them. Example: zip([1, 3],[2, 4]) --> [[1, 2], [3,4]]
      var point_list = lon.zip(lat);
      //getting the declination angle and hour angle
      var d = ee.Number(dr).multiply(2*Math.PI).divide(365).subtract(1.39).sin().multiply(0.409);
      var w = 1; //assuming average of hour angle as 0 degrees
      var cosd1 = d.sin();
      var cosd2 = lat.sin();
      var cosd3 = d.cos();
      var cosd4 = lat.cos();
      var cosd01 = cosd1.multiply(cosd2);
      //print(cosd01);
      var cosd02 = cosd3.multiply(cosd4);
      var cosd = cosd01.add(cosd02);









      share














      I am using the formula for solar incidence angle : cosd = sin(a)sin(b) + cos(a)cos(b)cos(c), where a = 0.409sin((2pi/365)*DOY - 1.39), b = latitude of region and c = hour angle(taken as constant for daily estimates) the code for the formula is not working. My code:



      // Zoom to a location.


      Map.setCenter(80.34, 26.42); // Center on IIT Kanpur.
      var G = 1367;



      //dayofyear
      var sequence = ee.Array(ee.List.sequence(1, 365));



      //calculating the relative earth sun distance
      var dr = sequence.multiply(2).divide(365).multiply(Math.PI).cos().multiply(0.033).add(1);
      print(dr);



      //calculating the solar incidence angle
      //getting latitude and longitude of the geometry
      var l8 = ee.ImageCollection("LANDSAT/LC08/C01/T1_SR")
      .filterBounds(geometry);
      var first = ee.Image(l8.first()).clip(geometry);

      // get image projection
      var proj = first.select([0]).projection();
      // get coordinates image
      var latlon = ee.Image.pixelLonLat().reproject(proj);
      Map.addLayer(first, {bands:['B1'], min:0, max:500}, 'Image');



      // put each lon lat in a list
      var coords = latlon.select(['longitude', 'latitude'])
      .reduceRegion({
      reducer: ee.Reducer.toList(),
      geometry: geometry,
      scale: 30
      });
      var lat1 = ee.List(coords.get('latitude'));
      var lat = ee.Array(lat1);
      var lon = ee.List(coords.get('longitude'));
      // zip them. Example: zip([1, 3],[2, 4]) --> [[1, 2], [3,4]]
      var point_list = lon.zip(lat);
      //getting the declination angle and hour angle
      var d = ee.Number(dr).multiply(2*Math.PI).divide(365).subtract(1.39).sin().multiply(0.409);
      var w = 1; //assuming average of hour angle as 0 degrees
      var cosd1 = d.sin();
      var cosd2 = lat.sin();
      var cosd3 = d.cos();
      var cosd4 = lat.cos();
      var cosd01 = cosd1.multiply(cosd2);
      //print(cosd01);
      var cosd02 = cosd3.multiply(cosd4);
      var cosd = cosd01.add(cosd02);







      javascript google-earth-engine





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      asked 15 mins ago









      Bhumika OjhaBhumika Ojha

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