Doubt in Field CalculatorUsing ArcMap, how may I convert a shapefile to use decimal degrees?Displaying lat...
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Doubt in Field Calculator
Using ArcMap, how may I convert a shapefile to use decimal degrees?Displaying lat long values from XLS in ArcGIS Desktop?Correct coordinate systems, but trustworthy distance between points?How to measure correct distances in a project with OpenLayers background?Proper projected coordinate system for Minnesota for measuring areasNAD27 to NAD83, saving AFTER transformation?distance() function in field calculator gives unexpected resultsCreating a variable distance buffer in QGISApprox distance between any 2 longitudes at a given latitudeWhat geodetic reference system is QGIS using when providing latitude and longitude values for points using the field calculator?
I am working in an project.I have a point Shapefile its projection is NAD83(HARN)Pennslyvaniasouth(ftUS)*EPSG3365* when I measure its distance(between two points) it gives me the answer in feet .yes its acceptable for me.I also calculated its x-coordinate and y-coordinate for the points in field Calculator it displays me the answer in feet.This is the problem.In my company they are insisting me to show the LAT-LONG value in Decimal Degrees.Is it possible to show the Lat-long in Decimal degrees in QGIS?
qgis coordinate-system field-calculator latitude-longitude decimal-points
asked Nov 12 '13 at 6:23
ArunArun
77721334
add a comment |
I am working in an project.I have a point Shapefile its projection is NAD83(HARN)Pennslyvaniasouth(ftUS)*EPSG3365* when I measure its distance(between two points) it gives me the answer in feet .yes its acceptable for me.I also calculated its x-coordinate and y-coordinate for the points in field Calculator it displays me the answer in feet.This is the problem.In my company they are insisting me to show the LAT-LONG value in Decimal Degrees.Is it possible to show the Lat-long in Decimal degrees in QGIS?
qgis coordinate-system field-calculator latitude-longitude decimal-points
asked Nov 12 '13 at 6:23
ArunArun
77721334
It's not really clear what exactly you're trying to do. What do you mean by "calculated its lat-long"? What expression did you use in the field calculator? Do you simply want the geographic coordinates (latitude/longitude) for all the points in your layer?
– Jake
Nov 12 '13 at 8:56
@Jake let me properly explain "calculated its lat-long" means i calculated X-coordinate($X) and y-coordinate($Y) in field calculator. I am getting ($X ,$y) in feet but I want this in Decimal Degree.Is it possible to get in QGIS I am asking?
– Arun
Nov 12 '13 at 8:56
2
For that, you need to project your layer to a geographic coordinate system first: Select the layer, click "Layer / Save as", then choose a geographic CRS such as EPSG:4326. Then use the field calculator on this new layer to get the coordinates in latitude/longitude.
– Jake
Nov 12 '13 at 9:46
add a comment |
I am working in an project.I have a point Shapefile its projection is NAD83(HARN)Pennslyvaniasouth(ftUS)*EPSG3365* when I measure its distance(between two points) it gives me the answer in feet .yes its acceptable for me.I also calculated its x-coordinate and y-coordinate for the points in field Calculator it displays me the answer in feet.This is the problem.In my company they are insisting me to show the LAT-LONG value in Decimal Degrees.Is it possible to show the Lat-long in Decimal degrees in QGIS?
qgis coordinate-system field-calculator latitude-longitude decimal-points
asked Nov 12 '13 at 6:23
ArunArun
77721334
I am working in an project.I have a point Shapefile its projection is NAD83(HARN)Pennslyvaniasouth(ftUS)*EPSG3365* when I measure its distance(between two points) it gives me the answer in feet .yes its acceptable for me.I also calculated its x-coordinate and y-coordinate for the points in field Calculator it displays me the answer in feet.This is the problem.In my company they are insisting me to show the LAT-LONG value in Decimal Degrees.Is it possible to show the Lat-long in Decimal degrees in QGIS?
qgis coordinate-system field-calculator latitude-longitude decimal-points
qgis coordinate-system field-calculator latitude-longitude decimal-points
asked Nov 12 '13 at 6:23
ArunArun
77721334
asked Nov 12 '13 at 6:23
ArunArun
77721334
edited Nov 12 '13 at 8:52
Arun
asked Nov 12 '13 at 6:23
ArunArun
77721334
asked Nov 12 '13 at 6:23
ArunArun
77721334
asked Nov 12 '13 at 6:23
ArunArun
77721334
77721334
It's not really clear what exactly you're trying to do. What do you mean by "calculated its lat-long"? What expression did you use in the field calculator? Do you simply want the geographic coordinates (latitude/longitude) for all the points in your layer?
– Jake
Nov 12 '13 at 8:56
@Jake let me properly explain "calculated its lat-long" means i calculated X-coordinate($X) and y-coordinate($Y) in field calculator. I am getting ($X ,$y) in feet but I want this in Decimal Degree.Is it possible to get in QGIS I am asking?
– Arun
Nov 12 '13 at 8:56
2
For that, you need to project your layer to a geographic coordinate system first: Select the layer, click "Layer / Save as", then choose a geographic CRS such as EPSG:4326. Then use the field calculator on this new layer to get the coordinates in latitude/longitude.
– Jake
Nov 12 '13 at 9:46
add a comment |
It's not really clear what exactly you're trying to do. What do you mean by "calculated its lat-long"? What expression did you use in the field calculator? Do you simply want the geographic coordinates (latitude/longitude) for all the points in your layer?
– Jake
Nov 12 '13 at 8:56
@Jake let me properly explain "calculated its lat-long" means i calculated X-coordinate($X) and y-coordinate($Y) in field calculator. I am getting ($X ,$y) in feet but I want this in Decimal Degree.Is it possible to get in QGIS I am asking?
– Arun
Nov 12 '13 at 8:56
2
For that, you need to project your layer to a geographic coordinate system first: Select the layer, click "Layer / Save as", then choose a geographic CRS such as EPSG:4326. Then use the field calculator on this new layer to get the coordinates in latitude/longitude.
– Jake
Nov 12 '13 at 9:46
It's not really clear what exactly you're trying to do. What do you mean by "calculated its lat-long"? What expression did you use in the field calculator? Do you simply want the geographic coordinates (latitude/longitude) for all the points in your layer?
– Jake
Nov 12 '13 at 8:56
It's not really clear what exactly you're trying to do. What do you mean by "calculated its lat-long"? What expression did you use in the field calculator? Do you simply want the geographic coordinates (latitude/longitude) for all the points in your layer?
– Jake
Nov 12 '13 at 8:56
@Jake let me properly explain "calculated its lat-long" means i calculated X-coordinate($X) and y-coordinate($Y) in field calculator. I am getting ($X ,$y) in feet but I want this in Decimal Degree.Is it possible to get in QGIS I am asking?
– Arun
Nov 12 '13 at 8:56
@Jake let me properly explain "calculated its lat-long" means i calculated X-coordinate($X) and y-coordinate($Y) in field calculator. I am getting ($X ,$y) in feet but I want this in Decimal Degree.Is it possible to get in QGIS I am asking?
– Arun
Nov 12 '13 at 8:56
2
2
For that, you need to project your layer to a geographic coordinate system first: Select the layer, click "Layer / Save as", then choose a geographic CRS such as EPSG:4326. Then use the field calculator on this new layer to get the coordinates in latitude/longitude.
– Jake
Nov 12 '13 at 9:46
For that, you need to project your layer to a geographic coordinate system first: Select the layer, click "Layer / Save as", then choose a geographic CRS such as EPSG:4326. Then use the field calculator on this new layer to get the coordinates in latitude/longitude.
– Jake
Nov 12 '13 at 9:46
add a comment |
1 Answer
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I think transform() function was not available when the question was posted (Y2013).
Now we can solve this CRS issue, just by the Field Calculator!
For Longitude: ...... x(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
For Latitude: ......... y(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
I created three random points near Philadelphia, and the transform() worked as expected. (Imported to GoogleEarth as KML and made a visual check).
answered 11 mins ago
KazuhitoKazuhito
16k41882
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
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active
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votes
I think transform() function was not available when the question was posted (Y2013).
Now we can solve this CRS issue, just by the Field Calculator!
For Longitude: ...... x(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
For Latitude: ......... y(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
I created three random points near Philadelphia, and the transform() worked as expected. (Imported to GoogleEarth as KML and made a visual check).
answered 11 mins ago
KazuhitoKazuhito
16k41882
add a comment |
I think transform() function was not available when the question was posted (Y2013).
Now we can solve this CRS issue, just by the Field Calculator!
For Longitude: ...... x(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
For Latitude: ......... y(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
I created three random points near Philadelphia, and the transform() worked as expected. (Imported to GoogleEarth as KML and made a visual check).
answered 11 mins ago
KazuhitoKazuhito
16k41882
add a comment |
I think transform() function was not available when the question was posted (Y2013).
Now we can solve this CRS issue, just by the Field Calculator!
For Longitude: ...... x(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
For Latitude: ......... y(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
I created three random points near Philadelphia, and the transform() worked as expected. (Imported to GoogleEarth as KML and made a visual check).
answered 11 mins ago
KazuhitoKazuhito
16k41882
I think transform() function was not available when the question was posted (Y2013).
Now we can solve this CRS issue, just by the Field Calculator!
For Longitude: ...... x(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
For Latitude: ......... y(transform($geometry, 'EPSG:3365', 'EPSG:4326'))
I created three random points near Philadelphia, and the transform() worked as expected. (Imported to GoogleEarth as KML and made a visual check).
answered 11 mins ago
KazuhitoKazuhito
16k41882
answered 11 mins ago
KazuhitoKazuhito
16k41882
answered 11 mins ago
KazuhitoKazuhito
16k41882
answered 11 mins ago
KazuhitoKazuhito
16k41882
16k41882
add a comment |
add a comment |
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It's not really clear what exactly you're trying to do. What do you mean by "calculated its lat-long"? What expression did you use in the field calculator? Do you simply want the geographic coordinates (latitude/longitude) for all the points in your layer?
– Jake
Nov 12 '13 at 8:56
@Jake let me properly explain "calculated its lat-long" means i calculated X-coordinate($X) and y-coordinate($Y) in field calculator. I am getting ($X ,$y) in feet but I want this in Decimal Degree.Is it possible to get in QGIS I am asking?
– Arun
Nov 12 '13 at 8:56
2
For that, you need to project your layer to a geographic coordinate system first: Select the layer, click "Layer / Save as", then choose a geographic CRS such as EPSG:4326. Then use the field calculator on this new layer to get the coordinates in latitude/longitude.
– Jake
Nov 12 '13 at 9:46