Im stuck and having trouble with ￢P ∨ Q Prove: P → Q Planned maintenance scheduled April...
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Im stuck and having trouble with ￢P ∨ Q Prove: P → Q
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
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I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
61
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Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
61
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
add a comment |
I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
61
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
61
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
Hamish DochertyHamish Docherty
61
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
Hamish DochertyHamish Docherty
61
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
Hamish DochertyHamish Docherty
61
asked 4 hours ago
Hamish DochertyHamish Docherty
61
61
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
add a comment |
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
2
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 28 mins ago
Graham KempGraham Kemp
1,03418
add a comment |
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1 Answer
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1 Answer
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oldest
votes
active
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oldest
votes
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 28 mins ago
Graham KempGraham Kemp
1,03418
add a comment |
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 28 mins ago
Graham KempGraham Kemp
1,03418
add a comment |
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 28 mins ago
Graham KempGraham Kemp
1,03418
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 28 mins ago
Graham KempGraham Kemp
1,03418
answered 28 mins ago
Graham KempGraham Kemp
1,03418
answered 28 mins ago
Graham KempGraham Kemp
1,03418
answered 28 mins ago
Graham KempGraham Kemp
1,03418
1,03418
add a comment |
add a comment |
Hamish Docherty is a new contributor. Be nice, and check out our Code of Conduct.
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2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago