Strange output from QGIS Raster Terrain Analysis pluginGetting incorrect slope values from an ASTER DEM in...
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Strange output from QGIS Raster Terrain Analysis plugin
Getting incorrect slope values from an ASTER DEM in QGIS?Strange output from RSAGA topographic wetness index?Slope analysis from NED data gives crazy histogram?Slope layer with false results in QGIS?Unexpected results with Raster Terrain Analysis Plugin
This is closely related to several other questions on this site: here, here, here etc.
However, my issue is not resolved by following the answers provided.
I am using the Raster Terrain Analysis plugin in QGIS ver 2.14.3. I want to create a Slope layer based on SRTM imagery. I understand that confusion can arise because the lat-lon units are degrees, and the vertical units are in metres. I calculated the z-factor with the formula z = 1/(111320*cos(latitude*pi/180)) provided in this answer. Which gives 0.00000899928 (I'm using imagery which spans the equator so used latitude = 0).
However, I get a layer of either 0 or 90. It is very similar to the question here. Re-saving the layer with WGS84, or converting to UTM before using the plugin does not help.
I am able to produce a sensible looking Slope layer if I convert the CRS to World Mollweide, but I would like to know why it isn't working with CRS in degrees? What am I doing wrong? Or is it an issue with the plugin?
qgis raster qgis-plugins slope
asked 1 min ago
EcologyTomEcologyTom
17912
add a comment |
This is closely related to several other questions on this site: here, here, here etc.
However, my issue is not resolved by following the answers provided.
I am using the Raster Terrain Analysis plugin in QGIS ver 2.14.3. I want to create a Slope layer based on SRTM imagery. I understand that confusion can arise because the lat-lon units are degrees, and the vertical units are in metres. I calculated the z-factor with the formula z = 1/(111320*cos(latitude*pi/180)) provided in this answer. Which gives 0.00000899928 (I'm using imagery which spans the equator so used latitude = 0).
However, I get a layer of either 0 or 90. It is very similar to the question here. Re-saving the layer with WGS84, or converting to UTM before using the plugin does not help.
I am able to produce a sensible looking Slope layer if I convert the CRS to World Mollweide, but I would like to know why it isn't working with CRS in degrees? What am I doing wrong? Or is it an issue with the plugin?
qgis raster qgis-plugins slope
asked 1 min ago
EcologyTomEcologyTom
17912
add a comment |
This is closely related to several other questions on this site: here, here, here etc.
However, my issue is not resolved by following the answers provided.
I am using the Raster Terrain Analysis plugin in QGIS ver 2.14.3. I want to create a Slope layer based on SRTM imagery. I understand that confusion can arise because the lat-lon units are degrees, and the vertical units are in metres. I calculated the z-factor with the formula z = 1/(111320*cos(latitude*pi/180)) provided in this answer. Which gives 0.00000899928 (I'm using imagery which spans the equator so used latitude = 0).
However, I get a layer of either 0 or 90. It is very similar to the question here. Re-saving the layer with WGS84, or converting to UTM before using the plugin does not help.
I am able to produce a sensible looking Slope layer if I convert the CRS to World Mollweide, but I would like to know why it isn't working with CRS in degrees? What am I doing wrong? Or is it an issue with the plugin?
qgis raster qgis-plugins slope
asked 1 min ago
EcologyTomEcologyTom
17912
This is closely related to several other questions on this site: here, here, here etc.
However, my issue is not resolved by following the answers provided.
I am using the Raster Terrain Analysis plugin in QGIS ver 2.14.3. I want to create a Slope layer based on SRTM imagery. I understand that confusion can arise because the lat-lon units are degrees, and the vertical units are in metres. I calculated the z-factor with the formula z = 1/(111320*cos(latitude*pi/180)) provided in this answer. Which gives 0.00000899928 (I'm using imagery which spans the equator so used latitude = 0).
However, I get a layer of either 0 or 90. It is very similar to the question here. Re-saving the layer with WGS84, or converting to UTM before using the plugin does not help.
I am able to produce a sensible looking Slope layer if I convert the CRS to World Mollweide, but I would like to know why it isn't working with CRS in degrees? What am I doing wrong? Or is it an issue with the plugin?
qgis raster qgis-plugins slope
qgis raster qgis-plugins slope
asked 1 min ago
EcologyTomEcologyTom
17912
asked 1 min ago
EcologyTomEcologyTom
17912
asked 1 min ago
EcologyTomEcologyTom
17912
asked 1 min ago
EcologyTomEcologyTom
17912
asked 1 min ago
EcologyTomEcologyTom
17912
17912
add a comment |
add a comment |
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