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Exporting MapSeries using index layer NAME, instead of page number, in ArcPy?
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How can I write this python script to export each page in a MapSeries to a PDF, whilst using the MapSeries index layer NAME as the file name? At the moment, the script is configured to export using the page number.
Is it as simple as replacing 'ms.currentPageNumber' and 'pageNum' with 'ms.currentPageName' and 'pageNam'? And would the {0} need removing on the final line?
import arcpy, os, sys
relpath = os.path.dirname(sys.argv[0])
p = arcpy.mp.ArcGISProject("C:\Automation\Automation.aprx")
print ("project located")
l = p.listLayouts()[0]
print ("layouts listed")
if not l.mapSeries is None:
ms = l.mapSeries
if ms.enabled:
for pageNum in range(1, ms.pageCount + 1):
ms.currentPageNumber = pageNum
print("Exporting page {0} of {1}".format(str(ms.currentPageNumber), str(ms.pageCount)))
l.exportToPDF("C:\Users\Default\Production\Completed_certificates\Exported_PDF_file_{0}".format(str(ms.currentPageNumber) + ".pdf"))
arcpy arcgis-pro map-series
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
|
show 2 more comments
How can I write this python script to export each page in a MapSeries to a PDF, whilst using the MapSeries index layer NAME as the file name? At the moment, the script is configured to export using the page number.
Is it as simple as replacing 'ms.currentPageNumber' and 'pageNum' with 'ms.currentPageName' and 'pageNam'? And would the {0} need removing on the final line?
import arcpy, os, sys
relpath = os.path.dirname(sys.argv[0])
p = arcpy.mp.ArcGISProject("C:\Automation\Automation.aprx")
print ("project located")
l = p.listLayouts()[0]
print ("layouts listed")
if not l.mapSeries is None:
ms = l.mapSeries
if ms.enabled:
for pageNum in range(1, ms.pageCount + 1):
ms.currentPageNumber = pageNum
print("Exporting page {0} of {1}".format(str(ms.currentPageNumber), str(ms.pageCount)))
l.exportToPDF("C:\Users\Default\Production\Completed_certificates\Exported_PDF_file_{0}".format(str(ms.currentPageNumber) + ".pdf"))
arcpy arcgis-pro map-series
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
If there is not something more direct you could always use list comprehension with a search cursor on the index layer to write a dictionary with objectid and page name as its key value pairs. Then use the dictionary to switch page number (objectid) for page name.
– PolyGeo♦
Feb 21 '18 at 11:38
@PolyGeo The index layer is updated every day, with new features replacing those from the previous day. If I understand what you're suggesting, I could not write a dictionary of all map index features, as I don't know what they will be called each day.
– Theo F
Feb 21 '18 at 11:57
The dictionary would be written as part of this script using one line of code that takes a second or two to run. I don't think it being volatile will be an issue.
– PolyGeo♦
Feb 21 '18 at 12:01
@PolyGeo ok fair. But I'll have to research how to do that. However, is there definitely no such thing as ms.currentPageName?
– Theo F
Feb 21 '18 at 13:55
The documentation should tell you that. I have not had chance to look.
– PolyGeo♦
Feb 21 '18 at 15:56
|
show 2 more comments
How can I write this python script to export each page in a MapSeries to a PDF, whilst using the MapSeries index layer NAME as the file name? At the moment, the script is configured to export using the page number.
Is it as simple as replacing 'ms.currentPageNumber' and 'pageNum' with 'ms.currentPageName' and 'pageNam'? And would the {0} need removing on the final line?
import arcpy, os, sys
relpath = os.path.dirname(sys.argv[0])
p = arcpy.mp.ArcGISProject("C:\Automation\Automation.aprx")
print ("project located")
l = p.listLayouts()[0]
print ("layouts listed")
if not l.mapSeries is None:
ms = l.mapSeries
if ms.enabled:
for pageNum in range(1, ms.pageCount + 1):
ms.currentPageNumber = pageNum
print("Exporting page {0} of {1}".format(str(ms.currentPageNumber), str(ms.pageCount)))
l.exportToPDF("C:\Users\Default\Production\Completed_certificates\Exported_PDF_file_{0}".format(str(ms.currentPageNumber) + ".pdf"))
arcpy arcgis-pro map-series
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
How can I write this python script to export each page in a MapSeries to a PDF, whilst using the MapSeries index layer NAME as the file name? At the moment, the script is configured to export using the page number.
Is it as simple as replacing 'ms.currentPageNumber' and 'pageNum' with 'ms.currentPageName' and 'pageNam'? And would the {0} need removing on the final line?
import arcpy, os, sys
relpath = os.path.dirname(sys.argv[0])
p = arcpy.mp.ArcGISProject("C:\Automation\Automation.aprx")
print ("project located")
l = p.listLayouts()[0]
print ("layouts listed")
if not l.mapSeries is None:
ms = l.mapSeries
if ms.enabled:
for pageNum in range(1, ms.pageCount + 1):
ms.currentPageNumber = pageNum
print("Exporting page {0} of {1}".format(str(ms.currentPageNumber), str(ms.pageCount)))
l.exportToPDF("C:\Users\Default\Production\Completed_certificates\Exported_PDF_file_{0}".format(str(ms.currentPageNumber) + ".pdf"))
arcpy arcgis-pro map-series
arcpy arcgis-pro map-series
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
edited Feb 21 '18 at 11:35
PolyGeo♦
53.6k1780240
53.6k1780240
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
asked Feb 21 '18 at 11:10
Theo FTheo F
19810
19810
If there is not something more direct you could always use list comprehension with a search cursor on the index layer to write a dictionary with objectid and page name as its key value pairs. Then use the dictionary to switch page number (objectid) for page name.
– PolyGeo♦
Feb 21 '18 at 11:38
@PolyGeo The index layer is updated every day, with new features replacing those from the previous day. If I understand what you're suggesting, I could not write a dictionary of all map index features, as I don't know what they will be called each day.
– Theo F
Feb 21 '18 at 11:57
The dictionary would be written as part of this script using one line of code that takes a second or two to run. I don't think it being volatile will be an issue.
– PolyGeo♦
Feb 21 '18 at 12:01
@PolyGeo ok fair. But I'll have to research how to do that. However, is there definitely no such thing as ms.currentPageName?
– Theo F
Feb 21 '18 at 13:55
The documentation should tell you that. I have not had chance to look.
– PolyGeo♦
Feb 21 '18 at 15:56
|
show 2 more comments
If there is not something more direct you could always use list comprehension with a search cursor on the index layer to write a dictionary with objectid and page name as its key value pairs. Then use the dictionary to switch page number (objectid) for page name.
– PolyGeo♦
Feb 21 '18 at 11:38
@PolyGeo The index layer is updated every day, with new features replacing those from the previous day. If I understand what you're suggesting, I could not write a dictionary of all map index features, as I don't know what they will be called each day.
– Theo F
Feb 21 '18 at 11:57
The dictionary would be written as part of this script using one line of code that takes a second or two to run. I don't think it being volatile will be an issue.
– PolyGeo♦
Feb 21 '18 at 12:01
@PolyGeo ok fair. But I'll have to research how to do that. However, is there definitely no such thing as ms.currentPageName?
– Theo F
Feb 21 '18 at 13:55
The documentation should tell you that. I have not had chance to look.
– PolyGeo♦
Feb 21 '18 at 15:56
If there is not something more direct you could always use list comprehension with a search cursor on the index layer to write a dictionary with objectid and page name as its key value pairs. Then use the dictionary to switch page number (objectid) for page name.
– PolyGeo♦
Feb 21 '18 at 11:38
If there is not something more direct you could always use list comprehension with a search cursor on the index layer to write a dictionary with objectid and page name as its key value pairs. Then use the dictionary to switch page number (objectid) for page name.
– PolyGeo♦
Feb 21 '18 at 11:38
@PolyGeo The index layer is updated every day, with new features replacing those from the previous day. If I understand what you're suggesting, I could not write a dictionary of all map index features, as I don't know what they will be called each day.
– Theo F
Feb 21 '18 at 11:57
@PolyGeo The index layer is updated every day, with new features replacing those from the previous day. If I understand what you're suggesting, I could not write a dictionary of all map index features, as I don't know what they will be called each day.
– Theo F
Feb 21 '18 at 11:57
The dictionary would be written as part of this script using one line of code that takes a second or two to run. I don't think it being volatile will be an issue.
– PolyGeo♦
Feb 21 '18 at 12:01
The dictionary would be written as part of this script using one line of code that takes a second or two to run. I don't think it being volatile will be an issue.
– PolyGeo♦
Feb 21 '18 at 12:01
@PolyGeo ok fair. But I'll have to research how to do that. However, is there definitely no such thing as ms.currentPageName?
– Theo F
Feb 21 '18 at 13:55
@PolyGeo ok fair. But I'll have to research how to do that. However, is there definitely no such thing as ms.currentPageName?
– Theo F
Feb 21 '18 at 13:55
The documentation should tell you that. I have not had chance to look.
– PolyGeo♦
Feb 21 '18 at 15:56
The documentation should tell you that. I have not had chance to look.
– PolyGeo♦
Feb 21 '18 at 15:56
|
show 2 more comments
1 Answer
1
active
oldest
votes
You can get the value of any field in the dataset which is used to generate the map series by using the ms.pageRow.FIELD_NAME
Try this:
l.exportToPDF("C:\Path_to_Output\Exported_PDF_file_{0}".format(str(ms.pageRow.NAME_FIELD) + ".pdf", 300))
answered 8 mins ago
Mick_ehMick_eh
1
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1 Answer
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1 Answer
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active
oldest
votes
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oldest
votes
active
oldest
votes
You can get the value of any field in the dataset which is used to generate the map series by using the ms.pageRow.FIELD_NAME
Try this:
l.exportToPDF("C:\Path_to_Output\Exported_PDF_file_{0}".format(str(ms.pageRow.NAME_FIELD) + ".pdf", 300))
answered 8 mins ago
Mick_ehMick_eh
1
New contributor
Mick_eh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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You can get the value of any field in the dataset which is used to generate the map series by using the ms.pageRow.FIELD_NAME
Try this:
l.exportToPDF("C:\Path_to_Output\Exported_PDF_file_{0}".format(str(ms.pageRow.NAME_FIELD) + ".pdf", 300))
answered 8 mins ago
Mick_ehMick_eh
1
New contributor
Mick_eh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
You can get the value of any field in the dataset which is used to generate the map series by using the ms.pageRow.FIELD_NAME
Try this:
l.exportToPDF("C:\Path_to_Output\Exported_PDF_file_{0}".format(str(ms.pageRow.NAME_FIELD) + ".pdf", 300))
answered 8 mins ago
Mick_ehMick_eh
1
New contributor
Mick_eh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You can get the value of any field in the dataset which is used to generate the map series by using the ms.pageRow.FIELD_NAME
Try this:
l.exportToPDF("C:\Path_to_Output\Exported_PDF_file_{0}".format(str(ms.pageRow.NAME_FIELD) + ".pdf", 300))
answered 8 mins ago
Mick_ehMick_eh
1
New contributor
Mick_eh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 8 mins ago
Mick_ehMick_eh
1
New contributor
Mick_eh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 8 mins ago
Mick_ehMick_eh
1
answered 8 mins ago
Mick_ehMick_eh
1
1
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Mick_eh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor
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If there is not something more direct you could always use list comprehension with a search cursor on the index layer to write a dictionary with objectid and page name as its key value pairs. Then use the dictionary to switch page number (objectid) for page name.
– PolyGeo♦
Feb 21 '18 at 11:38
@PolyGeo The index layer is updated every day, with new features replacing those from the previous day. If I understand what you're suggesting, I could not write a dictionary of all map index features, as I don't know what they will be called each day.
– Theo F
Feb 21 '18 at 11:57
The dictionary would be written as part of this script using one line of code that takes a second or two to run. I don't think it being volatile will be an issue.
– PolyGeo♦
Feb 21 '18 at 12:01
@PolyGeo ok fair. But I'll have to research how to do that. However, is there definitely no such thing as ms.currentPageName?
– Theo F
Feb 21 '18 at 13:55
The documentation should tell you that. I have not had chance to look.
– PolyGeo♦
Feb 21 '18 at 15:56