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Insert missing values in categorized style


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1















In QGIS Bonn, when styling my layer to use the categorize option, I want to have all values within a range, for instance, 0 to 50000.



I am using the data from a CSV that has information about population density and I am using a grayscale to categorize it.



But the values are so different that 0 is white, 2000 is medium gray and 50000 is black.



This does not reflect the true differences between population per area and I do not want to add the missing integer values by hand, how do I do it?










share|improve this question




















  • 1





    A screenshot could be helpful. Also, you can change breaks as this example i.stack.imgur.com/dcS1k.jpg

    – aldo_tapia
    Jul 18 '18 at 12:12
















1















In QGIS Bonn, when styling my layer to use the categorize option, I want to have all values within a range, for instance, 0 to 50000.



I am using the data from a CSV that has information about population density and I am using a grayscale to categorize it.



But the values are so different that 0 is white, 2000 is medium gray and 50000 is black.



This does not reflect the true differences between population per area and I do not want to add the missing integer values by hand, how do I do it?










share|improve this question




















  • 1





    A screenshot could be helpful. Also, you can change breaks as this example i.stack.imgur.com/dcS1k.jpg

    – aldo_tapia
    Jul 18 '18 at 12:12














1












1








1








In QGIS Bonn, when styling my layer to use the categorize option, I want to have all values within a range, for instance, 0 to 50000.



I am using the data from a CSV that has information about population density and I am using a grayscale to categorize it.



But the values are so different that 0 is white, 2000 is medium gray and 50000 is black.



This does not reflect the true differences between population per area and I do not want to add the missing integer values by hand, how do I do it?










share|improve this question
















In QGIS Bonn, when styling my layer to use the categorize option, I want to have all values within a range, for instance, 0 to 50000.



I am using the data from a CSV that has information about population density and I am using a grayscale to categorize it.



But the values are so different that 0 is white, 2000 is medium gray and 50000 is black.



This does not reflect the true differences between population per area and I do not want to add the missing integer values by hand, how do I do it?







qgis qgis-3 style






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago









underdark

68.3k13177342




68.3k13177342










asked Jul 18 '18 at 11:21









gdf31gdf31

61




61








  • 1





    A screenshot could be helpful. Also, you can change breaks as this example i.stack.imgur.com/dcS1k.jpg

    – aldo_tapia
    Jul 18 '18 at 12:12














  • 1





    A screenshot could be helpful. Also, you can change breaks as this example i.stack.imgur.com/dcS1k.jpg

    – aldo_tapia
    Jul 18 '18 at 12:12








1




1





A screenshot could be helpful. Also, you can change breaks as this example i.stack.imgur.com/dcS1k.jpg

– aldo_tapia
Jul 18 '18 at 12:12





A screenshot could be helpful. Also, you can change breaks as this example i.stack.imgur.com/dcS1k.jpg

– aldo_tapia
Jul 18 '18 at 12:12










2 Answers
2






active

oldest

votes


















1














If you take 'graduated' instead of 'categorized', you can choose the number of classes. Eg 5 classes gives you



0-10000



10000-20000



20000-30000



etc.






share|improve this answer































    1














    A way to overcome this kind of problem is to use a non-linear reclassification of the data (for exemple using the square root of the value for representation, or log or exp or... depending of the actual distribution of the data).



    By reclassifying you could differentiate more at one end of the scale (for exemple square root will let you discriminate between low value by lowering more the high value than the low one)






    share|improve this answer























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      If you take 'graduated' instead of 'categorized', you can choose the number of classes. Eg 5 classes gives you



      0-10000



      10000-20000



      20000-30000



      etc.






      share|improve this answer




























        1














        If you take 'graduated' instead of 'categorized', you can choose the number of classes. Eg 5 classes gives you



        0-10000



        10000-20000



        20000-30000



        etc.






        share|improve this answer


























          1












          1








          1







          If you take 'graduated' instead of 'categorized', you can choose the number of classes. Eg 5 classes gives you



          0-10000



          10000-20000



          20000-30000



          etc.






          share|improve this answer













          If you take 'graduated' instead of 'categorized', you can choose the number of classes. Eg 5 classes gives you



          0-10000



          10000-20000



          20000-30000



          etc.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Jul 18 '18 at 11:32









          PieterBPieterB

          2,4811026




          2,4811026

























              1














              A way to overcome this kind of problem is to use a non-linear reclassification of the data (for exemple using the square root of the value for representation, or log or exp or... depending of the actual distribution of the data).



              By reclassifying you could differentiate more at one end of the scale (for exemple square root will let you discriminate between low value by lowering more the high value than the low one)






              share|improve this answer




























                1














                A way to overcome this kind of problem is to use a non-linear reclassification of the data (for exemple using the square root of the value for representation, or log or exp or... depending of the actual distribution of the data).



                By reclassifying you could differentiate more at one end of the scale (for exemple square root will let you discriminate between low value by lowering more the high value than the low one)






                share|improve this answer


























                  1












                  1








                  1







                  A way to overcome this kind of problem is to use a non-linear reclassification of the data (for exemple using the square root of the value for representation, or log or exp or... depending of the actual distribution of the data).



                  By reclassifying you could differentiate more at one end of the scale (for exemple square root will let you discriminate between low value by lowering more the high value than the low one)






                  share|improve this answer













                  A way to overcome this kind of problem is to use a non-linear reclassification of the data (for exemple using the square root of the value for representation, or log or exp or... depending of the actual distribution of the data).



                  By reclassifying you could differentiate more at one end of the scale (for exemple square root will let you discriminate between low value by lowering more the high value than the low one)







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jul 18 '18 at 11:55









                  J.RJ.R

                  3,302222




                  3,302222






























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